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2 years ago

1. What does the word “processing” in data pro- cessing mean?

Computers and Technology

2 answers:

blsea [12.9K]2 years ago

6 0

Answer:

Word processing is the process of creating and editing documents on a computer. It allows a user to create documents that mimic the format and style of a typical typewriter. It requires a computer and word processing software. A printer may also be used to create a physical copy of the document.

Explanation:

zlopas [31]2 years ago

3 0

1. Processing means any action that produces information from data, such as finding totals, averages, ratios, and. trends.
2. Names, addresses, and educational experience of employment candidates, consumers, and members of
professional organizations are some examples. They are data, but are also used as information, because they are
often needed as is, without processing.
5. A TPS merely records transactions and channels them into files and databases. It does not analyze the data nor
create any information. A DSS contains software that help make decisions. It provides useful information gleaned and manipulated from raw data.

You might be interested in

Write a program that displays the following pattern: ..\.\* .\.\*** \.\***** ******* \.\***** .\.\*** ..\.\* That is, seven line

nalin [4]

Answer:

public class StarPattern {

public static final int MAX_ROWS = 7;

public static void main(String []args){

for (int row = 1; row <= MAX_ROWS; row++) {

int numOfSpaces = getNumberOfSpaces(row);

int numOfStars = MAX_ROWS - (getNumberOfSpaces(row) * 2);

String spaces = printSpaces(numOfSpaces);

String stars = printStars(numOfStars);

System.out.println(spaces + stars);

}

public static int getNumberOfSpaces(int row) {

int rowOffset = (MAX_ROWS / 2) + 1;

return Math.abs(row-rowOffset);

}

public static String printSpaces(int num) {

String result = "";

for (int i = 0; i < num; i++) {

result += " ";

}

return result;

}

public static String printStars(int num) {

String result = "";

for (int i = 0; i < num; i++) {

result += "*";

}

return result;

}

Explanation:

So it sounds we need to make a diamond shape out of asterisks like this:

***

*****

*******

*****

***

There are 7 rows and each row has up to 7 characters. The pattern is also symmetrical which makes it easier. Before writing any code, let's figure out how we are going to determine the correct amount of spaces we need to print. There are a lot of ways to do this, but I'll just show one. Let's call the 4th row y=0. Above that we have row 3 which would be y=-1, and below is row 5 which is y=1. With 7 rows, we have y=-3 through y=3. The absolute value of the y value is how many spaces we need.

To determine the number of stars, we just double the number of spaces, then subtract this number from 7. This is because we can imagine that the same amount of spaces that are printed in front of the stars are also after the stars. We don't actually have to print the second set of spaces since it is just white space, but the maximum number of characters in a row is 7, and this formula will always make sure we have 7.

I hope this helps. If you need help understanding any part of the code, jsut let me know.

3 0

2 years ago

Advertising is organized around four distinct groups. The _____ group includes the photographers, the illustrators, video produc

borishaifa [10]

Answer:

Suppliers

Explanation:

There are FOUR distinct groups of Advertising namely:

The Advertisers
The Advertising Agencies
The Suppliers
Media

1.The Advertisers : clients

2.The Advertising Agencies: The companies that prepare promotional

materials.

3.The Suppliers: Includes photographers, graphic designers, video recording

specialists.

4.Media: launches the promotional/advertising campaigns in pursuit to reach

the target audience.

4 0

2 years ago

Charles Mott works for a company called VeriSign that acts a trusted third party to verify information. One of Charles' largest

balu736 [363]

Answer:

Option (B) i.e., Certificate authority is the correct option to the following question.

Explanation:

The following option is correct because it an organization or company who validating the identification of that object that exists and it also verifies the information of the third party.

Option A is incorrect because it is the tool or software that protects the system from the outsiders or the malware.

Option b is incorrect because Online certificate is issued for any software or application or the certification in the field of study.

8 0

3 years ago

Why won't Brainly let me send a link? This is just du*mb! I want to send good articles explaining a content, and this site just

Basile [38]

Answer:

Maybe is against the community

Explanation:

4 0

3 years ago

Problem 1: you must write a method for this problem called sentenceAnalyzer Write a program that reads a sentence from the keybo

forsale [732]

Answer:

static void sentenceAnalyzer(String sentence){

int lenOfString = sentence.length()-1;

if(sentence.charAt(lenOfString)=='.'){

System.out.println("Declarative");

}

else if(sentence.charAt(lenOfString)=='?'){

System.out.println("Interrogative");

}

else if(sentence.charAt(lenOfString)=='!'){

System.out.println("Exclamation");

}

else{

System.out.println("Unknown");

}

Explanation:

Using Java programming language

Create the method as required

Obtain the index of the last element using the string length method

Use if and else statements to check if the character at the last index is equal to any of the characters given and print the expected output

see a complete code with the main method below

import java.util.Scanner;

public class num11 {

public static void main(String[] args) {

Scanner in = new Scanner(System.in);

//Receiving User input

System.out.println("Enter a sentence");

String sentence = in.nextLine();

// Calling the method

sentenceAnalyzer(sentence);

}

static void sentenceAnalyzer(String sentence){

int lenOfString = sentence.length()-1;

if(sentence.charAt(lenOfString)=='.'){

System.out.println("Declarative");

}

else if(sentence.charAt(lenOfString)=='?'){

System.out.println("Interrogative");

}

else if(sentence.charAt(lenOfString)=='!'){

System.out.println("Exclamation");

}

else{

System.out.println("Unknown");

}

}

8 0

3 years ago