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nikitadnepr [17]
3 years ago
7

How many times greater is 1 gallon than one quart

Mathematics
1 answer:
Lemur [1.5K]3 years ago
5 0
<span>well 1 gallon is 4 quarts so 4 times greater</span>
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Raina has 3 buckets.
Daniel [21]

Answer:

30/3=10

so every bucket gets 10 liters

Step-by-step explanation:

4 0
3 years ago
I'm giving brainliest to the most helpful answer. For 50 points:
Alenkinab [10]

Answer:

1) \displaystyle\frac{5}{18}\approx27.78\%

2) \displaystyle\frac{4}{7}\approx57.14\%

3) \displaystyle  \frac{13}{16}=81.25\%

Step-by-step explanation:

We are given a two-way frequency table. Using the table, we will determine the probability for each case.

Question 1)

P(A Student With A Part Time Job Without A Car)

Using the first column, the total number of students that have a part time job is 78+30=108.

Likewise, using the first column, we can see that out of those 108 students, 30 do not have a car.

Hence, the probability that a student with a part time job without a car is:

\displaystyle P=\frac{30}{108}=\frac{5}{18}\approx27.78\%

Question 2)

P(No Car | Does Not Have A Part Time Job)

Remember that the vertical line means conditional probability.

So, we want the probability of a student having no car given that they do not have a part time job.

Using the second column, we can see that the total number of students that do not have a part time job is 18+24=42.

Likewise, using the second column, 24 do not have a car.

Hence, the probability that a student with a part time job without a car is:

\displaystyle P=\frac{24}{42}=\frac{4}{7}\approx57.14\%

Question 3)

P(Part Time Job | Car)

So, we want to probability of a student having a part time job given that they have a car.

Using the first row, the total students that have a car is 78+18=96.

And of those 96 students, 78 have a part time job.

Hence, the probability that a student with a car has a part time job is given by:

\displaystyle P=\frac{78}{96}=\frac{13}{16}=81.25\%

4 0
3 years ago
Please help me
swat32

Answer: C

Step-by-step explanation:

Use Desmos | Graphing Calculator <33 This app/website works wonders fro math

4 0
3 years ago
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HELP PLEASE!!!!!!!!!!
Mazyrski [523]

Answer:

4?

Step-by-step explanation:

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3 years ago
Which of the following graphs could be the graph of the function f(x) = x4 + x3 – x2 – x?
vitfil [10]

<u> Solution-</u>

The given function is,

f(x) = x^4+ x^3-x^2-x

     = x^3(x+1)- x(x+1)

     = (x+1)(x^3-x)

     = (x+1)x(x^2-1)

     = (x+1)x(x+1)(x-1)

     = {(x+1)}^2x(x-1)

Therefore, at x=0, -1, 1 , f(x) will be 0 . Hence, 0, -1 ,1 are the x-intercepts.

Plotting the graph on desmos, the graph will be as in the attachment.

7 0
4 years ago
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