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Juli2301 [7.4K]

3 years ago

7

PLEASE HELP!!!!!!!! What is the 8th term of this sequence? 1,-1/2,1/4,-1/8

1 answer:

Tom [10]3 years ago

7 0

This is a geometric sequence with first term 1 and common ratio -1/2. r=-1/2.

a(n) = a(1)*(r)^(n-1).

Check: If n=2 our formula must return -1/2. Does it?

a(2) = 1(-1/2)^(2-1) = (-1/2)^1 = - 1/2. Yes.
a(3) should be 1/4. Is it? a(3) = (-1/2)^(3-1) = 1/4 Yes.

Then a(8) = (-1/2)^(8-1) = (-1/2)^7 = -1 / 2^7 = -1/128 (answer)

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Which equation represents a line that passes through (4, 5) and has a slope of ?

Nadusha1986 [10]

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B

Step-by-step explanation:

To find the answer, we can use the point-slope form:

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7 0

3 years ago

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a dice cube has 6 sides that are numbered 1-6. If the cube is thrown once, what is the probability of rolling an odd number?

I am Lyosha [343]

Answer:

3/6 or 1/2

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1, 2, 3, 4, 5, 6

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3 years ago

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Substitute the values for a, b, and c into b2 – 4ac to determine the discriminant. Which quadratic equations will have two real

hoa [83]

Answer: $0=2x^2-7x-9\\0=4x^2-3x-1\\0=x^2-2x-8$

Step-by-step explanation:

We know that the standard quadratic equation is ax^2+bx+c=0

Let's compare all the given equation to it and , find discriminant.

1. a=2, b= -7, c=-9

$b^2-4ac=(-7)^2-4(2)(-9)=49+72>0$

So it has 2 real number solutions.

2. a=1, b=-4, c=4

$b^2-4ac=(-4)^2-4(1)(4)=16-16=0$

So it has only 1 real number solution.

3. a=4, b=-3, c=-1

$b^2-4ac=(-3)^2-4(4)(-1)=9+16=25>0$

So it has 2 real number solutions.

4. a=1, b=-2, c=-8

$b^2-4ac=(-2)^2-4(1)(-8)=4+32=36>0$

So it has 2 real number solutions.

5. a=3, b=5, c=3

$b^2-4ac=(5)^2-4(3)(3)=25-36=-9$

Thus it does not has real solutions.

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3 years ago

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