Given/equations formed from text:
I: l=w+3
II: A=l*w
III: new area B=(l-2)*w
IV: B=A-30
substitute l in II with I to remove l:
II': A=l*w=
(w+3)*w=
w^2+3w
substitute l in III with I to remove l:
III': B=(l-2)*w=
(w+3-2)*w=
(w+1)*w=
w^2+w
substitute A and B from II' and III' into IV:
B=A-30
w^2+w=w^2+3w-30
30=2w
w=15
insert w=15 into I:
l=15+3=18
->
A) dimensions of full size rectangle are width 15 and length 18
dimensions of reduced size rectangle are width 15 and length 16
B) full size: 15*18=10*18+5*18=180+90=270cm^2
reduced size: 15*16=10*16+5*16=160+80=240cm^2
X = 36/5
Or x = 7.2
21 + x = 6x - 15
21 = 6x - 15 - x
21 = 5x - 15
21 + 15 = 5x
36 = 5x
36/5 = x
8.850 kg of flour will be left.
i’m not sure how to explain it
Answer:
x=15
Step-by-step explanation:
3(2x+5)=3x+4x
6x+15=3x+4x. *multiplied parentheses by 3*
15=3x+4x+-6. *moves all x to one side*
15=× * added
x=15
This could be wrong but the answer should be 4