It is D. After realizing the inequality to y>1, you can find D. To get y>1, you can see that there is a dotted line so there is no equal to and then you find that all y values are greater than 1 so we figure out it is D!
Answer:
x=y-6/3y+1
Step-by-step explanation:
3xy+x=y−6
Step 1: Factor out variable x.
x(3y+1)=y−6
Step 2: Divide both sides by 3y+1.
x(3y+1)
3y+1
=
y−6
3y+1
X+y+5=0
y=-x-5
If a solution exists y=y so we can say
x^2-9x+10=-x-5 add x+5 to both sides
x^2-8x+15=0 now factor
x^2-3x-5x+15=0
x(x-3)-5(x-3)
(x-5)(x-3) so x=3 and 5, using y=-x-5
y(3)=-8 and y(5)=-10
So the two solutions are:
(3,-8) and (5,-10)
Separate the quadratic functions into two individual function in x which multiply together to equal the original quadratic.
Eg: x^2-3x-10=0 can be written as (x+2)(x-5)=0
The two solutions for x can then be determined by making each bracket equal to zero.
x+2=0 so x=-2x-5=0 so x=5
Answer:
D
Step-by-step explanation:
