Answer: B. 1125
The answer is B because there is a special method when dividing by 3 to make sure it is actually able to be divided. You add the all the digits together, for example the digits in 1125, the total sum is 9 and if the total sum is able to be be divided by 3 then the whole number can be divided by 3.
Let a = 693, b = 567 and c = 441
Now first we will find HCF of 693 and 567 by using Euclid’s division algorithm as under
693 = 567 x 1 + 126
567 = 126 x 4 + 63
126 = 63 x 2 + 0
Hence, HCF of 693 and 567 is 63
Now we will find HCF of third number i.e., 441 with 63 So by Euclid’s division alogorithm for 441 and 63
441 = 63 x 7+0
=> HCF of 441 and 63 is 63.
Hence, HCF of 441, 567 and 693 is 63.
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Answer:
Step-by-step explanation:
The answer is A. 16+10+20= 46
the last two ones be the same, the outcomes would be TTT,HTT,THH,HHH
so the probability is 4/8 = 1/2.