A^2=-42+13a solve by factoring ?

Mathematics

1 answer:

lutik1710 [3]3 years ago

6 0

$a^2=-42+13a\\
a^2-13a+42=0\\
a^2-6a-7a+42=0\\
a(a-6)-7(a-6)=0\\
(a-7)(a-6)=0\\
a=7 \vee a=6$

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