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VladimirAG [237]
3 years ago
13

write an equation for a circle that is centered at the origin and has a radius of 6. show your work.​

Mathematics
1 answer:
taurus [48]3 years ago
8 0

(x-h)^2 + (y-k)^2 = r^2

(x)^2 + (y)^2 = 36

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3(2d - 7) = (2 + 4d)2 <br> i need the steps
wolverine [178]

3(2d - 7) = (2 + 4d)2

distribute

3*2d -3*7 = 2*2 +2*4d

multiply

6d -21 = 4 +8d

subtract 6d from each side

6d-6d-21 = 4 +8d-6d

-21 = 4+2d

subtract 4 from each side

-21 -4 =4+2d-4

-25 =2d

divide by 2

-25/2 =d

3 0
4 years ago
The temperature in the morning was -4º, by noon it was 11º, What was the change in temperature?​
iVinArrow [24]

Answer:

15 degrees

Step-by-step explanation:

-4 + 4 = 0

4+11=15

5 0
3 years ago
Write the explicit formula that represents the geometric sequene -2,8,-32,128
Vladimir [108]
Well, is a geometric sequence, the first term's value is -2

to get the subsequent term's value, we'd multiply by "something" so-called the "common ratio"

well, if we simply just divide any of those values by the one before it, the quotient must be the "common ratio".

hmm say for exampl -32/8 = -4  <---- there's our common ratio

\bf n^{th}\textit{ term of a geometric sequence}\\\\&#10;a_n=a_1\cdot r^{n-1}\qquad &#10;\begin{cases}&#10;n=n^{th}\ term\\&#10;a_1=\textit{first term's value}\\&#10;r=\textit{common ratio}\\&#10;----------\\&#10;a_1=-2\\&#10;r=-4&#10;\end{cases}\implies a_n=-2 (-4)^{n-1}
4 0
3 years ago
Solve the system of equations.
horrorfan [7]
The possible ordered pairs to solve this system are (8, 14) and (6, -12).

To solve this, use the second equation, which is already solved for y and put it in for y in the first equation. From that you will simplify and solve for 0 to get:

-x^2 + 14x - 48 = 0

Factor this and solve to get the possible x values as 8 and 6. Then use them in either equation to find the appropriate values for y. 
3 0
3 years ago
Look at the expression below.
Blababa [14]

Answer:

the product of 5 and the Cubic root of ( X+7)

7 0
3 years ago
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