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Wewaii [24]
3 years ago
11

What is the value of x in the system of equations shown below? 5x + 4y = 1 y = 1 - 3

Mathematics
1 answer:
DaniilM [7]3 years ago
7 0
The solution to this system of equations is x = -3 and y = 4.
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Solve the following exponential equations.<br> 10^(x+1) − 10^(x−1) = 1287
Rudiy27

Answer:x=2.114

Step-by-step explanation:

Given

10^{x+1}-10^{x-1}=1287

10\times 10^x-\frac{10^x}{10}=1287

Let 10^x=y

10y-\frac{y}{10}=1287

\frac{100y-y}{10}=1287

99y=1287\times 10

y=\frac{12870}{99}=130

10^x=130

Taking \logboth sides

x\log (10)=\log (130)

x=\frac{\log (130)}{1}

x=2.114

7 0
3 years ago
Using base ten blocks subtraction
GREYUIT [131]
Is their any multiple questions

4 0
3 years ago
the ratio of the ages of two children is 2:3. If the younger child is 4 years old, how old is the other child
yKpoI14uk [10]
Answer:  The other child is "6 years old". 
________________________________________________
Explanation:
________________________________________________

Set up the ratio as a fraction: 

  →  " 2/3 = 4/x " ;  Solve for "x"  (the age; in "years", of the "other child") ;  

<u>Note</u>:  GIven the ratios of two children is: 2:3  ; and there is a younger child among the two children;  the number "2" would represent the "younger child; since there are 2 (two) children;  and there are 2 (two) numbers in the given ratios; and among the 2 (two) numbers given in the ratio  — which are:  "2" and "3" ;  the given number: "2" is LESS THAN the given number "3" ; 

As such:
____________________________________________________
 
  →   " 2/3 = 4/x " ;  Solve for "x" ;  

Cross-multiply; 

2x = 3*4 ; 

2x = 12 ;

Divide each side of the equation by "2" ; 
 to isolate "x" on one side of the equation; & to solve for "x" ; 

2x/2 = 12/2 ; 

to get:
_______________________________________________
" x = 6 "
_______________________________________________
Alternate method:
_______________________________________________

Set up the ratio:
_____________________________________________

   →  " 2/3 = 4/x " ;  Solve for "x" ;   

Recognize that:  "2/3 = 4/6" ;  and that:  "x = 6" ; 
______________________________________________
Alternate method:
______________________________________________
Set up the ratio:
_______________________________________________

   →  " 2/3 = 4/x " ;  Solve for "x" ;   

In the "numerator":  → " 2 * [what value?] = 4 ? "
   → To find that value:  " 4 ÷ 2 = "2 " . 

As such:  Multiply the given:  "3" in the "denominator" by "2" ; to get: 
_______________________________________________
"3 * 2 = "x" ;   ↔  " x = 6 " . 
_______________________________________________
Answer:  The other child is "6 years old". 
_______________________________________________
Check our answer: 

The given ratio:  2/3 =? 4/6 ?  Yes! 

{You can even check this using a calculator—if you wish.}.
_______________________________________________
5 0
3 years ago
Please answer ! will give brainliest
kotegsom [21]

Answer:

7

Step-by-step explanation:

5 0
3 years ago
Left on together, the cold and hot water faucets of a certain bathtub take 5 minutes to fill the tub. If it takes the hot water
mario62 [17]

Answer:

\frac{15}{2}=7.5 minutes.

Step-by-step explanation:

Let t represent time taken by cold water faucet in minutes to fill the tub.

Part of tub filled by cold water faucet in one minute would be \frac{1}{t}.

We have been given that it takes the hot water faucet 15 minutes to fill the tub by itself, so art of tub filled by hot water faucet in one minute would be \frac{1}{15}.

We are also told that left on together, the cold and hot water faucets of a certain bathtub take 5 minutes to fill the tub, so part of tub filled by both faucets in one minute would be \frac{1}{5}.

We can represent part of tank filled by both faucets in one minute as:

\frac{1}{15}+\frac{1}{t}=\frac{1}{5}

\frac{1}{15}\cdot 15t+\frac{1}{t}\cdot 15t=\frac{1}{5}\cdot 15t

t+15=3t

t-t+15=3t-t

15=2t

2t=15

\frac{2t}{2}=\frac{15}{2}

t=7.5

Therefore, it will take 7.5 minutes for the cold water faucet to fill the tub alone.

8 0
3 years ago
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