Question

Mr. McGloughlin’s horses eat a total of 19 liters 2 deciliters of rolled oats, and drink a total of 46 liters 4 deciliters of water every day. How many liters of oats and water do the horses consume in one week combined?

Answer 1

19 liters and 2 deciliters =192 deciliter and 464 deciliter adding them we have 65 liters and 6 deciliters.

Answer 2

Answer:

459.2 liters.

Step-by-step explanation:

Let us convert our given amount of rolled oats and water in deciliters.

1 liter = 10 deciliters

19 liters = 19*10 deciliters = 190 deciliters.

$\text{Total amount of rolled oats consumed per day}=(190+2)\text{ deciliters}$

$\text{Total amount of rolled oats consumed per day}=192\text{ deciliters}$

46 liters=46*10=460 deciliters

$\text{Total amount of water consumed per day}=(460+4)\text{ deciliters}$

$\text{Total amount of water consumed per day}=464\text{ deciliters}$

Now let us find weekly consumption of oats and water by multiplying daily consumption of both items by 7.

$\text{Total weekly consumption of oats and water}=7*(464+192)\text{ deciliters}$

$\text{Total weekly consumption of oats and water}=7*(656)\text{ deciliters}$  

$\text{Total weekly consumption of oats and water}=4592\text{ deciliters}$

Let us convert weekly consumption of water and oats into liters.

$\text{Total weekly consumption of oats and water}=\frac{4592\text{ deciliters}}{10\frac{\text{ deciliters}}{\text{liter}}}$  

$\text{Total weekly consumption of oats and water}=\frac{4592\text{ deciliters}}{10}\cdot\frac{\text{ liters}}{\text{ deciliters}}}$

$\text{Total weekly consumption of oats and water}=\frac{4592}{10}\text{ liters}$

$\text{Total weekly consumption of oats and water}=459.2\text{ liters}$

Therefore, total weekly combined consumption of oats and water is 459.2 liters.