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3 years ago

Please help! CORRECT answer gets Brainliest Asnwer, please only respond if you understand the question and your answer!

Mathematics

1 answer:

Stella [2.4K]3 years ago

4 0

I’d make the spinner slices into thirds that are even because there would be an equal chance for each slice to be chosen. If I were to spin the spinner, I would have an equal 33.33% chance that it would land on $3, $5, or -$6. This makes it fair because they would all have an equal chance to be chosen!

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Which of the following is an example of a permutation?

Yuki888 [10]

Permutation

Step-by-step explanation:

Permutation is an example of the mathematics in which item are arranged in different way.
For example ABC, ACB, BCA, CBA, CAB, BAC etc.
The order of an arrangement are different in each alphabet.
The product of number also be defined as in the form of n to 1
for example : 5*4*3*2*1 = 120

Learn more: permutation

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3 years ago

Find the slope of the line that passes through (23, -30) and (-7, 18).

babymother [125]

Answer:

slope = - $\frac{8}{5}$

Step-by-step explanation:

Calculate the slope m using the slope formula

m = $\frac{y_{2}-y_{1} }{x_{2}-x_{1} }$

with (x₁, y₁ ) = (23, - 30) and (x₂, y₂ ) = (- 7, 18)

m = $\frac{18-(-30)}{-7-23}$ = $\frac{18+30}{-30}$ = $\frac{48}{-30}$ = - $\frac{8}{5}$

6 0

3 years ago

What is the Composite Surface Area? Need help asap is due today.

jok3333 [9.3K]

I’m really not sure but 216 because bass multiplied by height multiplied by width (6*6*6)

4 0

3 years ago

Thirteen percent of the profits from Kendall’s business are donated to charities.write and solve an equation to find out how muc

pychu [463]

The amount given to charity from Kendall’s profit is $168.0146

Given:

Kendall’s profit = $1292.42
Percentage given to charity = 13%

<h3>How to find percentage</h3>

Amount given to charity = Percentage given to charity × Kendall’s profit

= 13% of $1292.42

= 13/100 × 1292.42

= 0.13 × 1292.42

= $168.0146

Therefore, the amount given to charity from Kendall’s profit is $168.0146

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2 years ago

Evaluate the interval (Calculus 2)

Darya [45]

Answer:

$2 \tan (6x)+2 \sec (6x)+\text{C}$

Step-by-step explanation:

<u>Fundamental Theorem of Calculus</u>

$\displaystyle \int \text{f}(x)\:\text{d}x=\text{F}(x)+\text{C} \iff \text{f}(x)=\dfrac{\text{d}}{\text{d}x}(\text{F}(x))$

If differentiating takes you from one function to another, then integrating the second function will take you back to the first with a constant of integration.

Given indefinite integral:

$\displaystyle \int \dfrac{12}{1-\sin (6x)}\:\:\text{d}x$

$\boxed{\begin{minipage}{5 cm}\underline{Terms multiplied by constants}\\\\$\displaystyle \int a\:\text{f}(x)\:\text{d}x=a \int \text{f}(x) \:\text{d}x$\end{minipage}}$

If the terms are multiplied by constants, take them outside the integral:

$\implies 12\displaystyle \int \dfrac{1}{1-\sin (6x)}\:\:\text{d}x$

Multiply by the conjugate of 1 - sin(6x) :

$\implies 12\displaystyle \int \dfrac{1}{1-\sin (6x)} \cdot \dfrac{1+\sin(6x)}{1+\sin(6x)}\:\:\text{d}x$

$\implies 12\displaystyle \int \dfrac{1+\sin(6x)}{1-\sin^2(6x)} \:\:\text{d}x$

$\textsf{Use the identity} \quad \sin^2 x+ \cos^2 x=1:$

$\implies \sin^2 (6x) + \cos^2 (6x)=1$

$\implies \cos^2 (6x)=1- \sin^2 (6x)$

$\implies 12\displaystyle \int \dfrac{1+\sin(6x)}{\cos^2(6x)} \:\:\text{d}x$

Expand:

$\implies 12\displaystyle \int \dfrac{1}{\cos^2(6x)}+\dfrac{\sin(6x)}{\cos^2(6x)} \:\:\text{d}x$

$\textsf{Use the identities }\:\: \sec \theta=\dfrac{1}{\cos \theta} \textsf{ and } \tan\theta=\dfrac{\sin \theta}{\cos \theta}:$

$\implies 12\displaystyle \int \sec^2(6x)+\dfrac{\tan(6x)}{\cos(6x)} \:\:\text{d}x$

$\implies 12\displaystyle \int \sec^2(6x)+\tan(6x)\sec(6x) \:\:\text{d}x$

$\boxed{\begin{minipage}{5 cm}\underline{Integrating $\sec^2 kx$}\\\\$\displaystyle \int \sec^2 kx\:\text{d}x=\dfrac{1}{k} \tan kx\:\:(+\text{C})$\end{minipage}}$

$\boxed{\begin{minipage}{6 cm}\underline{Integrating $ \sec kx \tan kx$}\\\\$\displaystyle \int \sec kx \tan kx\:\text{d}x= \dfrac{1}{k}\sec kx\:\:(+\text{C})$\end{minipage}}$

$\implies 12 \left[\dfrac{1}{6} \tan (6x)+\dfrac{1}{6} \sec (6x) \right]+\text{C}$

Simplify:

$\implies \dfrac{12}{6} \tan (6x)+\dfrac{12}{6} \sec (6x)+\text{C}$

$\implies 2 \tan (6x)+2 \sec (6x)+\text{C}$

Learn more about indefinite integration here:

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3 0

2 years ago