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3 years ago

If x+y = -1, and xy= -12, what is the value of (x+3) (y+3) ?

Mathematics

1 answer:

9966 [12]3 years ago

7 0

Answer:

Here are my hints. You can solve it yourself

1/ xy = -12 --> x = -12/y

2/ (-12/y) + y = -1 --> -(12/y) + (y²/y) = -1 --> -12 + y² = -y --> y²+y-12=0

3/ From y²+y-12=0 we can find y then use y to find x and then do your

(x+3) * (y+3)

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PLZ HELP ASAP. (25 points)

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I need help solving for x

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Ayuda necesito resolver este problema con procedimiento ;)

Paraphin [41]

$x^3-2x^2+x-1$ is one of the prime factors of the polynomial

<h3>How to factor the expression?</h3>

The question implies that we determine one of the prime factors of the polynomial.

The polynomial is given as:

$x^8 - 3x^6 + x^4 - 2x^3 - 1$

Expand the polynomial by adding 0's in the form of +a - a

$x^8 - 3x^6 + x^4 - 2x^3 - 1 = x^8 -2x^7 + 2x^7 - 4x^6 +x^6 + 2x^5 -2x^5- 3x^4 + 4x^4 + 2x^3 -6x^3+2x^3- x^2 -3x^2 +4x^2-2x+2x-1$

Rearrange the terms

$x^8 - 3x^6 + x^4 - 2x^3 - 1 = x^8 -2x^7 + 2x^5 - 3x^4 + 2x^3 - x^2 + 2x^7 - 4x^6 + 4x^4 -6x^3+4x^2-2x+x^6-2x^5+2x^3-3x^2+2x-1$

Factorize the expression

$x^8 - 3x^6 + x^4 - 2x^3 - 1 = x^2(x^6-2x^5+2x^3-3x^2+2x-1) + 2x(x^6-2x^5+2x^3-3x^2+2x-1) + 1(x^6-2x^5+2x^3-3x^2+2x-1)$

Factor out x^6-2x^5+2x^3-3x^2+2x-1

$x^8 - 3x^6 + x^4 - 2x^3 - 1 = (x^2+2x + 1)(x^6-2x^5+2x^3-3x^2+2x-1)$

Express x^2 + 2x + 1 as a perfect square

$x^8 - 3x^6 + x^4 - 2x^3 - 1 = (x+1)^2(x^6-2x^5+2x^3-3x^2+2x-1)$

Expand the polynomial by adding 0's in the form of +a - a

$x^8 - 3x^6 + x^4 - 2x^3 - 1 = (x+1)^2(x^6- 2x^5+x^4-x^4-x^3 +x^3-2x^3-x^2 -2x^2 +x+x - 1)$

Rearrange the terms

$x^8 - 3x^6 + x^4 - 2x^3 - 1 = (x+1)^2(x^6- 2x^5+x^4-x^3-x^4-2x^3-x^2+x+x^3-2x^2 +x - 1)$

Factorize the expression

$x^8 - 3x^6 + x^4 - 2x^3 - 1 = (x+1)^2(x^3(x^3-2x^2+x-1) -x(x^3-2x^2+x-1)+1(x^3-2x^2+x-1))$

Factor out x^3-2x^2+x-1

$x^8 - 3x^6 + x^4 - 2x^3 - 1 = (x+1)^2(x^3 -x+1)(x^3-2x^2+x-1)$

One of the factors of the above polynomial is $x^3-2x^2+x-1$ .

This is the same as the option (c)

Hence, $x^3-2x^2+x-1$ is one of the prime factors of the polynomial

Read more about polynomials at:

brainly.com/question/4142886

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A. she would make 480 calls in a 5 day work week

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Write the equation of the line that is parallel to the line y=−14x−3 through the point (4,4).

statuscvo [17]

Hello there! :)

Parallel lines have the same slope, so if one line has a slope of -14, then the line parallel to it has a slope of -14 as well.

We are also given a point that the line passes through.

That's enough information to find the equation of the line.

First, we write the equation in point-slope form, which looks like so:

y-y1=m(x-x1)

y1 is the y-coordinate of the point, m is the slope of the line and x1 is the x-coordinate of the point.

y-4=-14(x-4)

y-4=-14x+56

y=-14x+60

Hence, that's the equation. Hope it helps.

~A lonely teen who helps others with a smile

-Grace

Good luck.

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2 years ago