1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
pshichka [43]
3 years ago
13

Premises: All flowers are beautiful. All roses are flowers. Conclusion: All roses are beautiful

Mathematics
1 answer:
Alona [7]3 years ago
3 0

Answer:

The conclusion is valid because the set of roses lying inside beautiful.

The required diagram is shown below:

Step-by-step explanation:

Consider the provided statement.

Premises: All flowers are beautiful. All roses are flowers.

Conclusion: All roses are beautiful

It is given that All roses are flowers that means all roses are the subset of flowers.

Now, it is given that All flowers are beautiful, that means all flowers are the subset of beautiful.

Thus, the required conclusion will consist all roses are the subset of flowers and all flowers are the subset of beautiful.

Therefore, the conclusion is valid because the set of roses lying inside beautiful.

The required diagram is shown below:

You might be interested in
The stream of water from a fountain follows a parabolic path. The stream reaches a maximum height of 7 feet, represented by a ve
xenn [34]

First of all, I'm going to assume that we have a concave down parabola, because the stream of water is subjected to gravity.

If we need the vertex to be at x=4, the equation will contain a (x-4)^2 term.

If we start with y=-(x-4)^2 we have a parabola, concave down, with vertex at x=4 and a maximum of 0.

So, if we add 7, we will translate the function vertically up 7 units, so that the new maximum will be (4, 7)

We have

y = -(x-4)+7

Now we only have to fix the fact that this parabola doesn't land at (8,0), because our parabola is too "narrow". We can work on that by multiplying the squared parenthesis by a certain coefficient: we want

y = a(x-4)^2+7

such that:

  • a
  • when we plug x=8, we have y=0

Plugging these values gets us

0 = a(8-4)^2+7 \iff 16a+7=0 \iff a = -\dfrac{7}{16}

As you can see in the attached figure, the parabola we get satisfies all the requests.

3 0
3 years ago
Uation for x and enter your answer in the box below<br> --3x + 7 = -2
Varvara68 [4.7K]

Answer:

x = -3

Step-by-step explanation:

Step 1: Simplify signs

3x + 7 = -2

Step 2: Subtract 7 on both sides

3x = -9

Step 3: Divide both sides by 3

x = -3

8 0
3 years ago
Read 2 more answers
Please help simplify the problem
galina1969 [7]

all you will have to do is add the top number . you should D

8 0
3 years ago
Read 2 more answers
Lara bought 3 yards of fabric and a spool of thread for $28.10. If the spool of thread cost $1.25, how much did the fabric cost
Lyrx [107]

Answer: $8.95 per yard of fabric

Step-by-step explanation:

Define the following:

x = cost of fabric per yard

Make an equation:

⇒ 3x + 1.25 = 28.10

⇒ 3x = 26.85

⇒ x = 8.95

∴ $8.95 per yard of fabric

7 0
2 years ago
There are 3 islands A,B,C. Island B is east of island A, 8 miles away. Island C is northeast of A, 5 miles away and northwest of
Nostrana [21]

Answer:

The bearing needed to navigate from island B to island C is approximately 38.213º.

Step-by-step explanation:

The geometrical diagram representing the statement is introduced below as attachment, and from Trigonometry we determine that bearing needed to navigate from island B to C by the Cosine Law:

AC^{2} = AB^{2}+BC^{2}-2\cdot AB\cdot BC\cdot \cos \theta (1)

Where:

AC - The distance from A to C, measured in miles.

AB - The distance from A to B, measured in miles.

BC - The distance from B to C, measured in miles.

\theta - Bearing from island B to island C, measured in sexagesimal degrees.

Then, we clear the bearing angle within the equation:

AC^{2}-AB^{2}-BC^{2}=-2\cdot AB\cdot BC\cdot \cos \theta

\cos \theta = \frac{BC^{2}+AB^{2}-AC^{2}}{2\cdot AB\cdot BC}

\theta = \cos^{-1}\left(\frac{BC^{2}+AB^{2}-AC^{2}}{2\cdot AB\cdot BC} \right) (2)

If we know that BC = 7\,mi, AB = 8\,mi, AC = 5\,mi, then the bearing from island B to island C:

\theta = \cos^{-1}\left[\frac{(7\mi)^{2}+(8\,mi)^{2}-(5\,mi)^{2}}{2\cdot (8\,mi)\cdot (7\,mi)} \right]

\theta \approx 38.213^{\circ}

The bearing needed to navigate from island B to island C is approximately 38.213º.

8 0
3 years ago
Other questions:
  • 1.414213562 round to the nearest tenth
    12·2 answers
  • What is the missing letter in F S T F F S S E
    12·1 answer
  • What is 5-to-4 in a percent??
    10·1 answer
  • What checking account fees can be avoided through good record keeping?
    11·2 answers
  • Evaluate this expression for a = 2 and b = 3. (a+5)-(b/b-4)+2(b+3/a)
    10·1 answer
  • Which trigonometric functions are equivalent to cos ∅. There must be only 2 selections no more no less !
    13·1 answer
  • What is a mathematical expression indicating to a root of a quantity?
    5·1 answer
  • For ΔABC with A(–5, –4), B(3, –2), and C(–1, 6), M is the midpoint of
    10·1 answer
  • Evaluate the expression when, m=-2<br><br> m²-6m-5<br><br> (Thank you for your help!)
    14·1 answer
  • 4(k+1)=k+10,then 3k=<br><br>A. 3/2<br>B.5/2<br>C. 2<br>D. 6​
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!