Question

3^b=17 exponentials into log form

Answer 1

Solve for the real domain

$3^b = 17$

if  f(x) = g(x) , then ln (f(x)) =  ln (g(x))

$ln ( 3^b) = ln (17)$

$log _{a} (x^b) = b*log _{a} (x)$

$ln(3^b) = bln(3)$

$bln(3) = ln (17)$

Solve  $bln(3) = ln (17)$

$b = \frac{ln(17)}{ln(3)}$

hope this helps !.