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garik1379 [7]
2 years ago
12

Can someone please explain functions and how find the y intercept when in this form

Mathematics
1 answer:
Harrizon [31]2 years ago
5 0

Slope-intercept form:  y = mx + b

[m is the slope, b is the y-intercept or the y value when x = 0 --> (0, y) or the point where the line crosses through the y-axis]

Since you know:

m = -2         Substitute/plug it into the equation

y = mx + b

y = -2x + b     To find b, plug in the point (7, -4) into the equation

-4 = -2(7) + b

-4 = -14 + b     Add 14 on both sides to get "b" by itself

-4 + 14 = -14 + 14 + b

10 = b       Now that you found b or the y-intercept, plug it in

y = -2x + 10

So to find the y-intercept, just plug in the point you were given into the equation once you had substituted in the slope. The slope tells you how many/the number of units from each point.

Slope can also be seen as:

m=\frac{rise}{run}

"rise" is the number of units you go up(+ number) or down(- number) from each point. (y-axis)

"run" is the number of units you go to the right from each point (x-axis)

For example, if you were to graph this line,

you could first plot a point at the y-intercept (0, 10). To plot the next point, you use the slope -2 or -2/1. So from (0, 10) you would go down 2 units and to the right 1 unit, therefore the next point you would plot would be (1, 8)

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Answer:

y = 1, 1.319, 1.024, 0

Step-by-step explanation:

Given equation:

y=(1+x)\cos x

\textsf{when}\:x=0:

\begin{aligned} \implies y & =(1+0)\cos 0\\\implies y & = 1\end{aligned}

\textsf{when}\:x=\dfrac{\pi}{6}:

\begin{aligned} \implies y & =\left(1+\frac{\pi}{6}\right)\cos \left(\frac{\pi}{6}\right)\\\implies y & = 1.319\: \sf (3\:dp)\end{aligned}

\textsf{when}\:x=\dfrac{\pi}{3}:

\begin{aligned} \implies y & =\left(1+\frac{\pi}{3}\right)\cos \left(\frac{\pi}{3}\right)\\\implies y & = 1.024\: \sf (3\:dp)\end{aligned}

\textsf{when}\:x=\dfrac{\pi}{2}:

\begin{aligned} \implies y & =\left(1+\frac{\pi}{2}\right)\cos \left(\frac{\pi}{2}\right)\\\implies y & = 0\end{aligned}

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In general, a valid model is one whose estimated value is close to the real value. This kind of model is considered to be accurate. It must be somewhat near to the real value if it doesn't resemble the real value.

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In conclusion,  The estimated value of a model has to be somewhat close to the real value for the model to be considered valid. If the number of students who are either pleased or extremely satisfied remains close to 75 percent following Mateo's survey of more students, then Mateo's model is likely accurate. In any other scenario, the model cannot be trusted.

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