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Ugo [173]
3 years ago
6

Which relation is also a function? A, B, C, or D?

Mathematics
2 answers:
andrew-mc [135]3 years ago
8 0

Answer:

AorD

srry if im wrong its not B because some of them are not compatible

Step-by-step explanation:

bija089 [108]3 years ago
7 0
<h3>Answer: Choice D</h3>

===================================================

Explanation:

To have a function, we cannot have repeated x values. Put another way, we can't have any input go to more than one output. Choices A through C are not functions because....

  • Choice A has x = 10 go to more than one y output.
  • Choice B has x = 2 go to more than one y output.
  • Choice C has x = 4 go to multiple y outputs.

Only choice D has each x value listed one time. We don't have any repeated x values. Any x input leads to exactly one y output. This is why choice D is a function.

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Solve using the fundamental theorem of algerba
Olin [163]

Answer:

No. of x-intercepts is equal to the no. of distinct species factors of a polynomial

Since this curve has only one distinct factor i.e (x+7)

The only x-intercepts is -7

(-7,0)

Y intercept would be at (0+7)⁷

Which is (0,7⁷)

Or (0,823543)

Since it's an odd power, branch of the curve for x > 7 would approach positive infinity

Branch for x < 7 would approach negative infinity

5 0
3 years ago
A graph shows height (inches) labeled 56 to 72 on the horizontal axis and shoe size on the vertical axis. A line shows an upward
olga2289 [7]

Answer:

A -a linear relationship showing as height increases, shoes size increases.

Step-by-step explanation:

7 0
3 years ago
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Find the product mentally.
nataly862011 [7]

Step-by-step explanation:

A is the answer to the question

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3 years ago
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Please help! I can't figure this out, i'll give a brainliest
Rus_ich [418]

The linear equation that best fits the data is: y = 10x + 15.

<h3>How to Write the Linear Equation of a Data?</h3>

First, find the slope/unit rate (m) and the y-intercept/starting value, then substitute the values into y = mx + b.

Using two points on the graph, (1, 25) and (2, 35), find the slope (m):

Slope (m) = (35 - 25)/(2 - 1)

Slope (m) = 10/1

Slope (m) = 10

Substitute (x, y) = (1, 25) and m = 10 into y = mx + b to find b

25 = 10(1) + b

25 - 10 = b

b = 15

Substitute m = 10 and b = 15 into y = mx + b

y = 10x + 15

Learn more about the linear equation on:

brainly.com/question/15602982

#SPJ1

3 0
2 years ago
Determine the horizontal vertical and slant asymptote y=x^2+2x-3/x-7
lilavasa [31]

Answer:

<h2>A.Vertical:x=7</h2><h2>Slant:y=x+9</h2>

Step-by-step explanation:

f(x)=\dfrac{x^2+2x-3}{x-7}\\\\vertical\ asymptote:\\\\x-7=0\qquad\text{add 7 to both sides}\\\\\boxed{x=7}\\\\horizontal\ asymptote:\\\\\lim\limits_{x\to\pm\infty}\dfrac{x^2+2x-3}{x-7}=\lim\limits_{x\to\pm\infty}\dfrac{x^2\left(1+\frac{2}{x}-\frac{3}{x^2}\right)}{x\left(1-\frac{7}{x}\right)}=\lim\limits_{x\to\pm\infty}\dfrac{x\left(1+\frac{2}{x}-\frac{3}{x^2}\right)}{1-\frac{7}{x}}=\pm\infty\\\\\boxed{not\ exist}

slant\ asymptote:\\\\y=ax+b\\\\a=\lim\limits_{x\to\pm\infty}\dfrac{f(x)}{x}\\\\b=\lim\limits_{x\to\pm\infty}(f(x)-ax)\\\\a=\lim\limits_{x\to\pm\infty}\dfrac{\frac{x^2+2x-3}{x-7}}{x}=\lim\limits_{x\to\pm\infty}\dfrac{x^2+2x-3}{x(x-7)}=\lim\limits_{x\to\pm\infty}\dfrac{x^2+2x-3}{x^2-7x}\\\\=\lim\limits_{x\to\pm\infty}\dfrac{x^2\left(1+\frac{2}{x}-\frac{3}{x^2}\right)}{x^2\left(1-\frac{7}{x}\right)}=\lim\limits_{x\to\pm\infty}\dfrac{1+\frac{2}{x}-\frac{3}{x^2}}{1-\frac{7}{x}}=\dfrac{1}{1}=1

b=\lim\limits_{x\to\pm\infty}\left(\dfrac{x^2+2x-3}{x-7}-1x\right)=\lim\limits_{x\to\pm\infty}\left(\dfrac{x^2+2x-3}{x-7}-\dfrac{x(x-7)}{x-7}\right)\\\\=\lim\limits_{x\to\pm\infty}\left(\dfrac{x^2+2x-3}{x-7}-\dfrac{x^2-7x}{x-7}\right)=\lim\limits_{x\to\pm\infty}\dfrac{x^2+2x-3-(x^2-7x)}{x-7}\\\\=\lim\limits_{x\to\pm\infty}\dfrac{x^2+2x-3-x^2+7x}{x-7}=\lim\limits_{x\to\pm\infty}\dfrac{9x-3}{x-7}=\lim\limits_{x\to\pm\infty}\dfrac{x\left(9-\frac{3}{x}\right)}{x\left(1-\frac{7}{x}\right)}

=\lim\limits_{x\to\pm\infty}\dfrac{9-\frac{3}{x}}{1-\frac{7}{x}}=\dfrac{9}{1}=9\\\\\boxed{y=1x+9}

8 0
3 years ago
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