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3 years ago

Which relation is also a function? A, B, C, or D?

Mathematics

2 answers:

andrew-mc [135]3 years ago

8 0

Answer:

AorD

srry if im wrong its not B because some of them are not compatible

Step-by-step explanation:

bija089 [108]3 years ago

7 0

<h3>Answer: Choice D</h3>

===================================================

Explanation:

To have a function, we cannot have repeated x values. Put another way, we can't have any input go to more than one output. Choices A through C are not functions because....

Choice A has x = 10 go to more than one y output.
Choice B has x = 2 go to more than one y output.
Choice C has x = 4 go to multiple y outputs.

Only choice D has each x value listed one time. We don't have any repeated x values. Any x input leads to exactly one y output. This is why choice D is a function.

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X−3(5x−6)=3−10x What is x, and how do you find x?

Fudgin [204]

Answer:

x=3or-1

Step-by-step explanation:

x-3 (5x-6)=3-10x

5x^2-15x-6x+18=3-10x

collect like terms

5x^2+18-3=15x+6x-10x

5x^2+15=11x

5x^2-11x+15=0

factorise

(x-3) (5x+5) =0

...... x=3 or -1

pls like if helpful nd rank me as most helpful ans

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4 years ago

2 to the power 948 equals what

Natali5045456 [20]

Hello,

2^948=2,3792270535644529004768999970398e+285
=2379227053564452900476899997039840896210016322655031134489234974905505051456646997672269303193850160943677958064308756880727336392871849132465328929763831401252753344715935798308298255734876378992382713251762299529708397931004608141051358304557852932819272168726630260518024558103494656

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4 years ago

Please help me on this!

sashaice [31]

How does the $100 gift card affect the measure of center of the data?

It increases the mean value of the prizes.

It decreases the mean value of the prizes.

It increases the median value of the prizes.

It decreases the median value of the prizes.

8 0

4 years ago

Order the numbers in each list from least to greatest. <br>0,|-14|, 13, -12, |-16|,17

Mrac [35]

Answer:

-12, 0, 13, [-14], [-16], 17

Step-by-step explanation:

3 0

4 years ago

Can somebody help me with all three problems please

Lerok [7]

1. $x^{2} -10x +25 = 0$

These two numbers are: -5 and -5

-5 + (-5) = -10

-5 * -5 = 25

so...

(x - 5)(x - 5)

To find the roots set the factored numbers equal to zero and solve for x:

x - 5 = 0

x = 5

2. $x^{2} + 9x = -14$

This equation needs to be equal to zero, so bring -14 to the other side by adding 14 to both sides

$x^{2}+9x+14 =0$

Find two numbers that the sum is equal to 9 AND the multiplication of the numbers is 14

These numbers are 7 and 2

7 + 2 = 9

7*2 = 14

so...

(x + 2) (x + 7)

To find the roots set the each of the factored numbers equal to zero and solve for x:

x + 2 = 0

x = -2

x + 7 = 0

x = -7

3. $3x^{2} = 6x$

This equation needs to be equal to zero, so bring 6x to the other side by subtracting 6x to both sides

$3x^{2} -6x = 0$

In this equation you can factor out a 3 and an x:

3x (x - 2)

To find the roots set the each of the factored numbers equal to zero and solve for x:

3x = 0

3x/3 = 0/3

x = 0

x - 2 = 0

x = 2

Hope this helped!

8 0

4 years ago