Question

I have no idea!! Please help!!!

Answer 1

The area of a traingle is $\frac{1}{2}bh$
So we need to know the base and the height
To work out the sides of a right angle triangle we can use a²+b²=c
c is the hypotenuse and a and b are the other sides
Because this triangle is isoceles we know that a and b are the same

a²+b²=c²
a²+a²=c²
2a²=c²
2a²=(x√6)²
2a²=(x√6)(x√6)
2a²=x²+x√6+x√6+6
2a²=x²+x√6+x√6+6
a²=$\frac{x^{2}+x \sqrt{6}+x \sqrt{6}+6 }{2}$
a=$\sqrt{\frac{x^{2}+x\sqrt{6}+x\sqrt{6}+6}{2}}$

A=$\frac{1}{2}bh$
A=$\frac{1}{2}a*a$
A=$\frac{1}{2}$×$\sqrt{\frac{x^{2}+x\sqrt{6}+x\sqrt{6}+6}{2}}$×$\sqrt{\frac{x^{2}+x\sqrt{6}+x\sqrt{6}+6}{2}}$
A=$\frac{1}{2}$×$\frac{x^{2}+x \sqrt{6}+x \sqrt{6}+6 }{2}$
A=$\frac{x^{2}+x \sqrt{6}+x \sqrt{6}+6 }{4}$