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shutvik [7]
4 years ago
10

What is -3 1/3 = -1/2g

Mathematics
1 answer:
Firdavs [7]4 years ago
8 0

Answer:

g = 62/3 or

g  = 20 \frac{2}{3}

Step-by-step explanation:

-  \frac{31}{3}  =  -  \frac{1}{2} g \\  -  \frac{31}{3}  \times ( - 2) = g \\  \frac{62}{3}  = g \\ g =  \frac{62}{3}  \\ g = 20 \frac{2}{3}

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1. Find domain of the function, = ln(2 − 6 − 55).
Bingel [31]
Domain of a function

We want to find the domain of the following function:

=ln\mleft(^2-6-55\mright)

This means that we want to find the x-values that it can take.

<h2>STEP 1: analyzing the simplies form of the function</h2>

Let's analyze the simpliest form of the function:

=ln(x)

Its graph is:

Then, for the simpliest form of the function, the x-values can only be higher than 0.

This means that its domain is

domain = x > 0

<h2>STEP 2: domain of the given function</h2>

Based on the above we can deduce that for the <em>ln(x)</em> function, what is inside the parenthesis should be higher than 0 on this kind of functions.

This is that for

=ln\mleft(^2-6-55\mright)

then

^2-6-55>0<h2>STEP 3: finding the x values that make x²-6x-55>0 (factoring)</h2>

In order to find the values of x that make

^2-6-55>0

we must factor it.

We want to find a pair of numbers that when multiplied give the last term (-55) and when added together give the second term (-6).

For the last term of the polynomial: -55, we have that

(-5) · 11 = 55

5 · (-11) = 11

If we add them:

-5 + 11 = 6

5 - 11 = -6

The pair of numbers that when multiplied give the last term (-55) and when added together give the second term (-6), are: 5 and -11

We use them to factor the polynomial:

^2-6-55=(x+5)(x-11)

Then,

(x+5)(x-11)>0<h2>STEP 4: finding the x values that make (x+5)(x-11)>0 (factoring)</h2>

In order to find them, we are going to separate the factors (x+5) and (x-11) and analyze when they are positive or negative:

Combining them:

Since we are going to multiply both factors:

(x+5)(x-11)

We use the diagram to analyze the sign of their product:

Then

(x+5)(x-11)>0

when x < -5 and when x > 11. This is the domain.

Therefore, expressed in set notation:

domain = {x|x∈(-∞, -5)∪(11, ∞)}

<h2>Answer: domain = {x | x ∈ (-∞, -5)∪(11, ∞)}</h2>

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