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laila [671]
3 years ago
10

Cross multiply to get answer x + 5/10 = 2x-3/15

Mathematics
1 answer:
Andreyy893 years ago
3 0

Once cross multiplied you end up with this:

15x+75=20x−30

Next subtract 20x from both sides.

15x+75−20x=20x−30−20x

−5x+75=−30 -----------> Answer

Now subtract 75 from both sides

−5x+75−75=−30−75

−5x=−105

Now divide by -5 on both sides.

-5/-5x = -105/-5

<h3 /><h3>x = 21 --------------> ANSWER</h3>
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What does x2 + 11x + 24 look like on a graph
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The equation x^2 + 11x + 24 looks like this when graphed.

I hope this helps!

8 0
3 years ago
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Responde el siguiente problema de lógica: Al mirar el reloj, vemos que la manecilla de los minutos apunta a un número que casual
ANTONII [103]

Answer: 11:50

Step-by-step explanation:

Ok, la manecilla de los minutos apunta al numero X.

si la ora es Y, entonces Y + X = 12:00

podemos asumir que Y es 11:y

y es la cantidad de minutos despues de las 11, es un numero entre 0 y 59 (por que una hora solo puede tener 60 minutos)

Si la manecilla de los minutos apunta al numero 6 por ejemplo, entoces:

y = 11:30 y X = 6 min

X + y = 11:30 + 0:06 = 11:36

Así funciona.

la equacion es:

y = 5*X

y tambien queremos que:

X + y = 60min

reemplazo y por lo de la equacion de arriba:

X + y = X + 5*X = 6X = 60min

X = 10

Si la manecilla apunta al 10, tenemos que:

y = 11:50 y X = 10min

y + X = 11:50 + 0:10 = 12:00

Entonces podemos concluir que la hora es 11:50.

8 0
3 years ago
Can someone please help me
Airida [17]

Step-by-step explanation:

it is a simple addition and subtraction sequence :

10 + 0 + -21 + 14 = 3

since the result is positive, it is overall a gain.

if the result were negative, it would be an overall loss.

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5 0
3 years ago
The height (h) of a fireball launched from a Roman candle with an initial velocity of 64 feet per second is given by the equatio
Zigmanuir [339]

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3 0
4 years ago
Help me this question
lubasha [3.4K]

Answer:

(a) 218.6 N

(b) 97.14 N

Step-by-step explanation:

When the system is in equilibrium, the net torque on the system is zero.

AC = 1.5 m, CD = 2.3 m, DB = 5 - 1.5 - 2.3 = 1.2 m

Let the centre of gravity of plank is at G.

AG = 2.5 m, CG = 2.5 - 1.5 = 1 m, GB = 2.5 m

(a) Let the reaction at C is R and at D is R'.

R + R' = 29 x 9.8 = 284.2 N ... (1)

Take the torque about C.

29 x 9.8 x CG = R' x GD

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R = 97.14 N

8 0
3 years ago
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