The domain and range of a function is the set of input and output values, the function can take.
- <em>The domain is [0,6]</em>
- <em>The range is [0,90]</em>
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From the question, we have:

<u>The domain</u>
He cannot mow more than 6 yards a day.
This means that the domain is: 0 to 6
<em>This is properly represented as: [0,6]</em>
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<u>The range</u>
When he mows 0 yards, his earnings is:

When he mows 6 yards, his earnings is:

This means that the range is: 0 to 90
<em>This is properly represented as: [0,90]</em>
Read more about domain and range at:
brainly.com/question/4767962
Answer:
None
Step-by-step explanation:
By graphing out the both line segments through graphing software, segments AB and CD have no intersections on the co-ordinate plane.
I've attached a screenshot of what i graphed out.
<u>Not sure what you are asking for, but,</u>
<u>Here is an example of a JRU (Join Result Unknown) word problem</u>:
There were _____ kids on the playground. ____ more kids came onto the playground. How many kids are on the playground?
<u>Here is an example of a JCU (Join Change Unknown) word problem:</u>
There were ____ kids on the playground. Some more kids came on the playground. Now there are ____ kids on the playground. How many kids came on the playground?
<u>
Here is an example of a JSU (Join Start Unknown) word problem:</u>
Some kids were on the playground. ____ kids came on the playground. Now there are ____ kids on the playground. How many kids were on the playground at the beginning?
Answer:
Yes, there is enough evidence to say the proportions are the same.
Step-by-step explanation:
Null hypothesis: The proportions are the same.
Alternate hypothesis: The proportions are not the same.
Data given:
p1 = 51% = 0.51
n1 = 200
p2 = 48% = 0.48
n2 = 150
pooled proportion (p) = (n1p1 + n2p2) ÷ (n1 + n2) = (200×0.51 + 150×0.48) ÷ (200 + 150) = 174 ÷ 350 = 0.497
Test statistic (z) = (p1 - p2) ÷ sqrt[p(1-p)(1/n1 + 1/n2) = (0.51 - 0.48) ÷ sqrt[0.497(1-0.497)(1/200 + 1/150)] = 0.03 ÷ 0.054 = 0.556
The test is a two-tailed test. At 0.10 significance level the critical values -1.645 and 1.645
Conclusion:
Fail to reject the null hypothesis because the test statistic 0.556 falls within the region bounded by the critical values.