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dexar [7]
3 years ago
19

What are the solutions to the equation 0 = x2 – x –6? Select two options

Mathematics
2 answers:
KatRina [158]3 years ago
6 0

Answer:

x=3 or x=-2

Step-by-step explanation:

This is factorable.

The leading coefficient is 1.

Since this is a quadratic all we have to do is find two numbers that multiply to be c and add up to be b to factor the expression that is to the left of the equal sign.

By the way a quadratic expression looks like ax^2+bx+c.

So we want to find two numbers that multiply to be -6 and add up to be -1.

Those numbers are -3 and 2 since (-3)(2)=-6 and -3+2=-1.

So the factored form is:

(x-3)(x+2)=0.

Since we have a product is zero then at least one of the factors need to be zero in order for the equation to hold.

So this means we have the following two equations to solve:

x-3=0 or x+2=0

First equation we will add 3 on both sides.

Second equation we will subtract 2 on both sides.

x=3 or x=-2

Lemur [1.5K]3 years ago
5 0
(X-3)(x+2)=0

So, X=3,X= -2
X={3,-2}
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Can someone do this thanks and quickly:)
MArishka [77]

Answer:

This figure is a quadrilateral, and therefore the sum of the interior angles must be 360°.  Adding them up, we get 40° + 128° + x + 82° = 360°, or

168° + 82° + x = 360°, or  250° + x = 360.  Subtracting 250° from both sides results in 110°, which is the measure of x.

Step-by-step explanation:

3 0
3 years ago
In the figure, AB=12, BC=8, DE=6, PD=4, and A is the point of tangency. Find the radius of circle P.
Lelu [443]

Answer:

The radius of the circle P = 2√10 = 6.325

Step-by-step explanation:

∵ AB is a tangent to circle P at A

∴ (AB)² = BC × BE

∵ BC = 8 , AB = 12 , ED = 6

∵ BE = ED + DC + CB

∴ BE = 6 + CD + 8 = 14 + CD

∴ (12)² = 8 × (14 + DC) ⇒ (12)²/8 = 14 + CD ⇒ CD = (12)²/8 - 14

∴ CD = 4

Join PC and PE (radii)

In ΔBDC and ΔPDE ⇒ ∵ ∠PDC = Ф , ∴ ∠PDE = 180 - Ф

Use cos Rule:

∵ r² = (PD)² + (DC)² - 2(PD)(DC)cosФ

∴ r² = 16 + 16 - 32cosФ = 32 - 32cosФ ⇒ (1)

∵ r² = (PD)² + (DE)² - 2(PD)(DE)cos(180 - Ф) ⇒ cos(180 - Ф) = -cosФ

∴ r² = 16 + 36 + 48cosФ = 52 + 48cosФ ⇒ (2)

∵ (1) = (2)

∴ 32 - 32 cosФ = 52 + 48cosФ

∴ 32 - 52 = 48cosФ + 32cosФ

∴ -20 = 80cosФ

∴ cosФ = -20/80 = -1/4

∴ r² = 32 - 32(-1/4) = 32 + 8 = 40

∴ r = √40 = 2√10 = 6.325

7 0
3 years ago
2) Find the slope of the line
algol13
Assuming each line goes up by 1. we basically need to find a number that goes by rise/run. to get to the next point we need to go up 1, then to the left by 3. notice the slope is negative so we need to add a negative integer.

answer:

-1/3 (C)

hope this helps! :D
4 0
3 years ago
Read 2 more answers
Are both 7 and -½ integers? why or why not?​
Tems11 [23]

Answer:

No. (-1/2) is not an integer

Integers involve all the no. +ve and -ve. which can be written without fraction. ie whole no. are counted as integers.

(-1/2) is a fraction

4 0
2 years ago
Read 2 more answers
Im just typing this so i can reach the 20 character the limit :)​
masha68 [24]

Answer:

x = 5

Step-by-step explanation:

Add the degrees of m<VUJ and m<JUT and make them equal to 175 since both angles exist with m<VUT.

17x - 3 + 17x + 8 = 175

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34x + 5 = 175

34x = 170

x = 5

7 0
3 years ago
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