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3 years ago

The results for a survey of 120 students who were selected randomly are listed below.

Mathematics

1 answer:

RoseWind [281]3 years ago

7 0

Answer:

Company X - 190 students

Company Y - 114 students

No phones - 76 students

Step-by-step explanation:

1) Find a multiplier to get the ratio from sample to population; to compare the sample to the population

380/120 = 3.16666667 or 3 & 1/6

380 comes from the total population of students and 120 comes from the randomly selected.

2) Use our multiplier to compare the results to the population

People with Company X

60 * 3.16667 = 190

People with Company Y

36 * 3.166667 = 114

People with no cell phone

24 * 3.166667 = 76.0000000001 = 76 (rounded)

Double check

190 + 114 + 76 = 380

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lilavasa [31]

Answer:

y = -13x + 55

Step-by-step explanation:

perpendicular formula : m1 × m2 = -1

y = -13x + 4

now we take the grafient of the equation which is 13 :

m × 13 = -1

m = -13

so now we hv a new gradient then we can find the equation use the formula y = mx + c :

m = -13 point = ( 4 , 3 )

sub them into the formula,

3 = -13 (4) + c

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3 years ago

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Setler [38]

Answer:

$310\text{ feet and }210\text{ feet}$

Step-by-step explanation:

GIVEN: A farmer has $520 \text{ feet}$ of fencing to construct a rectangular pen up against the straight side of a barn, using the barn for one side of the pen. The length of the barn is $310 \text{ feet}$ .

TO FIND: Determine the dimensions of the rectangle of maximum area that can be enclosed under these conditions.

SOLUTION:

Let the length of rectangle be $x$ and $y$

perimeter of rectangular pen $=2(x+y)=520\text{ feet}$

$x+y=260$

$y=260-x$

area of rectangular pen $=\text{length}\times\text{width}$

$=xy$

putting value of $y$

$=x(260-x)$

$=260x-x^2$

to maximize $\frac{d \text{(area)}}{dx}=0$

$260-2x=0$

$x=130\text{ feet}$

$y=390\text{ feet}$

but the dimensions must be lesser or equal to than that of barn.

therefore maximum length rectangular pen $=310\text{ feet}$

width of rectangular pen $=210\text{ feet}$

Maximum area of rectangular pen $=310\times210=65100\text{ feet}^2$

Hence maximum area of rectangular pen is $65100\text{ feet}^2$ and dimensions are $310\text{ feet and }210\text{ feet}$

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