<em>1</em>×<em>4+1=5
2</em>×<em>5+2=12
3</em>×<em>6+3=21
So, 8</em>×<em>11+8=96</em>
Using the t-distribution, we have that the 95% confidence interval for the true mean number of pushups that can be done is (9, 21).
For this problem, we have the <u>standard deviation for the sample</u>, thus, the t-distribution is used.
- The sample mean is of 15, thus
. - The sample standard deviation is of 9, thus
. - The sample size is of 10, thus
.
First, we find the number of degrees of freedom, which is the one less than the sample size, thus df = 9.
Then, looking at the t-table or using a calculator, we find the critical value for a 95% confidence interval, with 9 df, thus t = 2.2622.
The margin of error is of:

Then:

The confidence interval is:

Then


The confidence interval is (9, 21).
A similar problem is given at brainly.com/question/25157574
27\1000 is your rational form.
Answer:
the first one
Step-by-step explanation:
a negative times or divided by another negative gives you a positive
a positive times or divide by a negative gives you a negative
a positive times or divide by a positive gives you a positive