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marishachu [46]
3 years ago
5

What is the 4th term in the sequence ?

Mathematics
1 answer:
Katena32 [7]3 years ago
6 0

Answer:

156

Step-by-step explanation:

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The diagram shows the distances, in feet, of paths between each farm animal. What is the total distance off the paths from the c
Ainat [17]

Answer:

Step-by-step explanation:

cow->chicken is 16

chicken->horse is 21

horse->pig is 7

pig->cow is 13

16+21+7+13=57

I  know the distances from each animal to the other. I was asked to find the perimeter, because the distances of the paths create a quadrilateral.

7 0
3 years ago
At what point on the paraboloid y = x2 + z2 is the tangent plane parallel to the plane 3x + 2y + 7z = 2? (if an answer does not
Nikitich [7]
If f(x, y, z) = c represent a family of surfaces for different values of the constant c. The gradient of the function f defined as \nabla f is a vector normal to the surface f(x, y, z) = c.

Given <span>the paraboloid

y = x^2 + z^2.

We can rewrite it as a scalar value function f as follows:

f(x,y,z)=x^2-y+z^2=0

The normal to the </span><span>paraboloid at any point is given by:

\nabla f= i\frac{\partial}{\partial x}(x^2-y+z^2) - j\frac{\partial}{\partial y}(x^2-y+z^2) + k\frac{\partial}{\partial z}(x^2-y+z^2) \\  \\ =2xi-j+2zk

Also, the normal to the given plane 3x + 2y + 7z = 2 is given by:

3i+2j+7k

Equating the two normal vectors, we have:
</span>
2x=3\Rightarrow x= \frac{3}{2}  \\  \\ -1=2 \\ \\ 2z=7\Rightarrow z= \frac{7}{2}

Since, -1 = 2 is not possible, therefore there exist no such point <span>on the paraboloid y = x^2 + z^2 such that the tangent plane is parallel to the plane 3x + 2y + 7z = 2</span>.
4 0
4 years ago
Consider the following two circles. Circle P with center (-1, 2) and radius 3 and circle Q with center (3, 4) radius 5. What seq
KonstantinChe [14]

Answer:

<h2>B. Dilation centered at P, followed by reflection across the y-axis and then the line y = -x + 5</h2>

Step-by-step explanation:

<h3>Circle P.</h3>

Centerat (-1, 2).

Radius of 3.

<h3>Circle Q.</h3>

Center at (3, 4).

Radius of 5.

To carry one circle onto the other, their centers and radius must be the same.

So, circle P must be shifted from (-1, 2) to (3, 4), that means the translation is 4 units to the right side and two units upside, this is the first transformation.

The second transformation must be about stretching the circle P, from a radius of 3 to a radius of 5.

Therefore, the right answer is B.

4 0
3 years ago
Estimate the size of a crowd walking in a charity fundraising march that occupies a rectangular space with dimensions of 10 feet
jolli1 [7]

Answer:

4000 is size of a crowd walking in a charity fundraising March.

Step-by-step explanation:

Given:

Dimensions of rectangular space 10 feet by 12000 feet

So we can say that,

Length = 1200 ft

Width = 10 ft

Now we will calculate the area of rectangular space which is given by

Hence Area will be = length\times width= 10\ ft \times 1200 \ ft= 12000 \ ft^2

Now we know that 40 people occupy a rectangle measuring 10 feet by 12 feet.

Length = 12 ft

Width = 10 ft

Area = length\times width= 10\ ft \times 12 \ ft= 120 \ ft^2

It says that 40 people are occupied in 120 ft^2

So how many people will be there in 12000 ft^2

By using unitary method we get,

Number of people = \frac{40\times 12000 \ ft^2}{120 \ ft^2} = 4000 \ peoples

Size of a crowd walking in a charity fundraising March is 4000.

8 0
4 years ago
Read 2 more answers
Idek how to start please help
sp2606 [1]

First, note that x+21 and 3x+9 are "complementary angles;" they add up to 90 degrees.  Thus, 4x + 30 = 90 degrees, so that 4x = 60 degrees, and x = 15 degrees.

6 0
3 years ago
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