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elixir [45]
3 years ago
6

What's the difference between an algebraic expression and an equation ?

Mathematics
1 answer:
GarryVolchara [31]3 years ago
5 0

Answer:an expression can include numbers, variables, operators, sets, matrices, and other single things that can all be evaluated to one thing. An equation is two expressions that are equal to each other. ... An equation is two expressions that are equal to each other.

Step-by-step explanation:

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Rzqust [24]
Exponential is the answer okau
5 0
2 years ago
15 POINTS! <br><br> help with this. image is attached...
Nikolay [14]

Answer:

50

Step-by-step explanation:

5³ ÷  (↓13 - 8) x 2

↓5³ ÷   5  x  2

125 ÷ 5 x 2

25 x 2

50

7 0
3 years ago
ASAP HELP PLEASE! I WILL MARK THE FASTEST CORRECT ANSWER BRAINLIEST<br> see attached
V125BC [204]

Answer:1.1 ft^2

Step-by-step explanation:

Φ=55°

Radius=r=4

π=3.14

Area of segment=area of sector - area of triangle

Area of sector=Φ/360 x π x r x r

area of sector=55/360 x 3.14 x 4 x 4

Area of sector=(55x3.14x4x4) ➗ 360

Area of sector=2763.2 ➗ 360

Area of sector=7.7 ft^2

Area of triangle=0.5 x r x r x sinΦ

Area of triangle=0.5 x 4 x 4 x sin55

Area of triangle=0.5 x 4 x 4 x 0.8192

Area of triangle=6.6 ft^2

Area of segment=area of sector - area of triangle

Area of segment=7.7-6.6

Area of segment=1.1 ft^2

4 0
4 years ago
How do you turn this equation into y=Mx+b form?
lana66690 [7]

Answer:

y= -4x + 54

Step-by-step explanation:

4x + y =54

-4x -4x

y = -4x +54

3 0
3 years ago
You need a 75% alcohol solution. On hand, you have a 1125 mL of a 90% alcohol mixture. How much pure water will you need to add
Alex777 [14]
\bf \begin{array}{lccclll}&#10;&amount&concentration&&#10;\begin{array}{llll}&#10;concentrated\\&#10;amount&#10;\end{array}\\&#10;&-----&-------&-------\\&#10;\textit{90\% sol'n}&1125&0.9&(1125)0.9\\&#10;\textit{water}&x&0&0x\\&#10;-----&-----&-------&-------\\&#10;mixture&y&0.75&0.75y&#10;\end{array}

so.. whatever "x" is, we know 1125 + x = y
and whatever the alcohol concentration yield may be, we know

(1125)(0.9) = 0.75y

(1125)(0.9) = 0.75y   <--- solve for "y", that's how much the final amount of milliliters will be

how much pure water was added? subtract 1125 from that, or y - 1125


5 0
3 years ago
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