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2 years ago

A number x plus 10 is more than 2

Mathematics

1 answer:

makvit [3.9K]2 years ago

4 0

X+10>2. The simplified answer is x>-8

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djyliett [7]

B explination ?????????,????,? &#£$£$£$£$£$???

3 0

2 years ago

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What improper fraction or mixed number is 30/20 in simplest form

True [87]

30/20= 1 and 10/20 in simplest form that is 1 and 1/2

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2 years ago

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What would Y be equal to in the problem 0.5x + 0.6y = 5.4

Alla [95]

Answer:

y = - $\frac{5}{6}$ x + 9

Step-by-step explanation:

0.5x + 0.6y = 5.4

0.6y = -0.5x + 5.4

Multiply 10 on all sides.

6y = -5x + 54

Divide 6 on all sides.

y = - $\frac{5}{6}$ x + 9

7 0

1 year ago

You are looking at the New York ball drop on New Year’s Eve at a distance of 100 m away from the base of the structure. If the b

Fofino [41]

The question is an illustration of related rates.

The rate of change between you and the ball is 0.01 rad per second

I added an attachment to illustrate the given parameters.

The representations on the attachment are:

$\mathbf{x = 100\ m}$

$\mathbf{\frac{dy}{dt} = 2\ ms^{-1}}$ ---- the rate

$\mathbf{\theta = \frac{\pi}{4}}$

First, we calculate the vertical distance (y) using tangent ratio

$\mathbf{\tan(\theta) = \frac{y}{x}}$

Substitute 100 for x

$\mathbf{y = 100\tan(\theta) }$

$\mathbf{\tan(\theta) = \frac{y}{100}}$

Differentiate both sides with respect to time (t)

$\mathbf{ \sec^2(\theta) \cdot \frac{d\theta}{dt} = \frac{1}{100} \cdot \frac{dy}{dt}}$

Substitute values for the rates and $\mathbf{\theta }$

$\mathbf{ \sec^2(\pi/4) \cdot \frac{d\theta}{dt} = \frac{1}{100} \cdot 2}$

This gives

$\mathbf{ (\sqrt 2)^2 \cdot \frac{d\theta}{dt} = \frac{1}{100} \cdot 2}$

$\mathbf{ 2 \cdot \frac{d\theta}{dt} = \frac{1}{100} \cdot 2}$

Divide both sides by 2

$\mathbf{ \frac{d\theta}{dt} = \frac{1}{100} }$

$\mathbf{ \frac{d\theta}{dt} = 0.01 }$

Hence, the rate of change between you and the ball is 0.01 rad per second