Answer:
The length of TQ is 14.
Step-by-step explanation:
The length of SV and VS are the same.
4x - 1 = 15
4x = 16
x = 4
Similarly, the length of TS and TQ are the same.
3x + 2 = 3(4) + 12 = 14
Answer: A = $1503.6
Step-by-step explanation:
We would apply the formula for determining compound interest which is expressed as
A = P(1 + r/n)^nt
Where
A = total amount in the account at the end of t years
r represents the interest rate.
n represents the periodic interval at which it was compounded.
P represents the principal or initial amount deposited
From the information given,
P = 1000
r = 6% = 6/100 = 0.06
n = 1 because it was compounded once in a year.
t = 7 years
Therefore,.
A = 1000(1 + 0.06/1)^1 × 7
A = 1000(1.06)^7
A = $1503.6
Answer and Step-by-step explanation:
Let x and y be two positive integers and their sum is 14:
X + y = 14
And the sum of square of this number is:
f = x2 + y2
= x2+ (14 – x)2
Differentiate with respect to x, we get:
F’(x) = [ x2 + (14 – x)2]’ = 0
2x + 2(14-x)(-1) = 0
2x +( 28 – 2x)(-1) = 0
2x – 28 +2x = 0
2x + 2x = 28
4x = 28
X = 7
Hence, y = 14 – x = 14 -7 = 7
Now taking second derivative test:
F”(x) > 0
For x = y = 7,f reaches its maximum value:
(7)2 + (7)2 = 49 + 49
= 98
F at endpoints x Є [ 0, 14]
F(0) = 02 + (14 – 0)2
= 196
F(14) = (14)2 + (14 – 14)2
= 196
Hence the sum of squares of these numbers is minimum when x = y = 7
And maximum when numbers are 0 and 14.
The answer is 3x^2-19x+1
(-4x+3)-(7x-3x^2-1)
-12x+7x+3x^2+1
Combine like terms:
3x^2+(-12x+-7x)+1
= 3x^2+-19x+1
Answer:
The current temperature on the X scale is 1150 °X.
Step-by-step explanation:
Let is determine first the ratio of change in X linear temperature scale to change in Y linear temperature scale:
The difference between current temperature in Y linear scale with respect to freezing point is:
The change in X linear scale is:
Lastly, the current temperature on the X scale is:
The current temperature on the X scale is 1150 °X.
