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3 years ago

Can some one plz help me with my geometry home work I really need help pleaseee

Mathematics

1 answer:

irga5000 [103]3 years ago

7 0

Answer:

What Do you need help with?

Step-by-step explanation:

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Use Definition 7.1.1, DEFINITION 7.1.1 Laplace Transform Let f be a function defined for t ≥ 0. Then the integral ℒ{f(t)} = ∞ e−

poizon [28]

$f(t)=\begin{cases}\cos t&\text{for }0\le t$

The Laplace transform is then

$\mathcal L_s\{f(t)\}=\displaystyle\int_0^\infty f(t)e^{-st}\,\mathrm dt=\int_0^\pi e^{-st}\cos t\,\mathrm dt$

Let $I$ denote the integral we want to compute. Integrating by parts, setting

$u=e^{-st}\implies\mathrm du=-se^{-st}\,\mathrm dt$

$\mathrm dv=\cos t\,\mathrm dt\implies v=\sin t$

gives

$\displaystyle I=e^{-st}\sin t\bigg|_{t=0}^{t=\pi}+s\int_0^\pi e^{-st}\sin t\,\mathrm dt$

Integrate by parts again, setting

$u=e^{-st}\implies\mathrm du=-se^{-st}\,\mathrm dt$

$\mathrm dv=\sin t\,\mathrm dt\implies v=-\cos t$

Then

$\displaystyle I=e^{-st}\sin t\bigg|_{t=0}^{t=\pi}+s\left(-e^{-st}\cos t\bigg|_{t=0}^{t=\pi}-s\int_0^\pi e^{-st}\cos t\,\mathrm dt\right)$

$I=e^{-st}(\sin t-s\cos t)\bigg|_{t=0}^{t=\pi}-s^2I$

$(s^2+1)I=s(e^{-\pi s}+1)$

$I=\dfrac s{s^2+1}(e^{-\pi s}+1)$

7 0

4 years ago

Complete the two-column proof.

IrinaVladis [17]

5x + 7x = 180 ⇒ properties of linear pair
12x = 80 ⇒ addition property (since (5 + 7)x = 12x)
x = 15 ⇒ Division property (since we divide both sides by 12)

8 0

4 years ago

Read 2 more answers

What is 3/10 plus 5/8

Svet_ta [14]

3/10+ 5/8
First find a common denominator
multiply top and bottom the same
12/40 +25/40
add
37/40

3 0

4 years ago

ANSWER PLEASE I NEED THIS

WITCHER [35]

Answer:

It’s the third one, the one that u r clicking on

Step-by-step explanation:

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3 years ago

Read 2 more answers

What is the value of x

Lostsunrise [7]

Answer: your answer is 36.3 cause it's half of 72.6.

Step-by-step explanation:

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3 years ago