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3 years ago

How many 2/3 penuts can be made with 8 ounces of penuts?

1 answer:

6 0

Divide
8/1 / 2/3
Keep change flip
8/1 x 3/2
Simplify
4/1 x 3/1
12/1
He can make 12 2/3 ounce peanuts with 8 ounces of peanuts.

You might be interested in

(9x−5/2) −(3−2x/3) −(8x−2/4 )=2

Ierofanga [76]

The answer for the equation is 21/5 or 4.2.

8 0

4 years ago

What is the span of the roof? A. 4 ft B. 12 ft C. 18 ft D. 24 ft

RoseWind [281]

Answer:

D. 24 ft

Step-by-step explanation:

The slope of 1/3 means the rise is 1/3 the run for each half of the span. The rise is shown as 4 ft, so the half-span is 3·4 ft = 12 ft.

The span of the roof is 24 ft.

4 0

3 years ago

Two shooters, Rodney and Philip, practice at a shooting range. They fire rounds each at separate targets. The targets are mark

Sedaia [141]

Complete Question

Answer:

$SE = 0.66}$

$-3.29 < \mu_1 - \mu_2 < -0.70$

Step-by-step explanation:

From the question we are told that

The sample size is n = 60

The first sample mean is $\= x _1 = 8$

The second sample mean is $\= x _2 = 10$

The first variance is $v_1 = 0.25$

The first variance is $v_2 = 0.55$

Given that the confidence level is 95% then the level of significance is 5% = 0.05

Generally from the normal distribution table the critical value of $\frac{\alpha }{2}$ is

$Z_{\frac{\alpha }{2} } = 1.96$

Generally the first standard deviation is

$\sigma_1 = \sqrt{v_1}$

=> $\sigma_1 = \sqrt{0.25}$

=> $\sigma_1 = 0.5$

Generally the second standard deviation is

$\sigma_2 = \sqrt{v_2}$

=> $\sigma_2 = \sqrt{0.55}$

=> $\sigma_2 = 0.742$

Generally the first standard error is

$SE_1 = \frac{\sigma_1}{\sqrt{n} }$

$SE_1 = \frac{0.5}{\sqrt{60} }$

$SE_1 = 0.06$

Generally the second standard error is

$SE_2 = \frac{\sigma_2}{\sqrt{n} }$

$SE_2 = \frac{0.742}{\sqrt{60} }$

$SE_2 = 0.09$

Generally the standard error of the difference between their mean scores is mathematically represented as

$SE = \sqrt{SE_1^2 + SE_2^2 }$

=> $SE = \sqrt{0.06^2 +0.09^2 }$

=> $SE = 0.66}$

Generally 95% confidence interval is mathematically represented as

$(\= x_1 -\= x_2) -(Z_{\frac{\alpha }{2} } * SE) < \mu_1 - \mu_2 < (\= x_1 -\= x_2) +(Z_{\frac{\alpha }{2} } * SE)$

=> $(8 -10) -(1.96 * 0.66) < \mu_1 - \mu_2 < (8-10) +(Z_{\frac{\alpha }{2} } * 0.66)$

=> $-3.29 < \mu_1 - \mu_2 < -0.70$

5 0

4 years ago

8 tens + 3 ones = ____ tens + 13 ones

tia_tia [17]

Answer:

7 tens

Step-by-step explanation:

the value of the first half of the statement is 83 and the value of the second one is 13 (without the tens) so that mean it has 70 left over to make it 7 tens.

4 0

4 years ago

Rico thinks of a number between 30 and 40 that is represented by

Anna007 [38]

Hello,

x,y,z∈ IN

$x=\frac{3}{4}*y$
$y=\frac{1}{3}*z$

$140$
$46\leq\ y\ \leq\ 50 ==>\ \frac{46*3}{4}\leq\frac{3y}{4}\leq\frac{50*3}{4}$
$35\ \leq\ z\ \leq\ 37$ ==>
x∈{35,36,37}
y∈{47,48,49}
z∈{141,144,147}

We must go futher:

if x=35 then y=4*35/3=46.666 not good , not whole
if x=36 then y=4*36/3=48 ok
if x=37 then y=37*4/3=49.333.. not good

So there is only one solution (36,48,144) for (x,y,z)

No problem with z for z=3/1*4/3*x=4x ==>whole.

7 0

3 years ago