X=small bag
y=large bag
5x+3y=260
4x+2y=200
(5x+3y=260)*4 =20x+12y=1040
(4x+2y=200)*5 =20x+10y=1000
subtract two equations: 2y=40
divide: y=20
plug y in 5x+3*20=260
simplify x=40
small bag=$40
large bag=$20
Use pythagorean theorem - a^2+ b^2 = c^2
a = 2ft, b = ?, c = 6ft
2 x 2 + b^2 = 6 x 6
4 + b^2 = 36
b^2 = 36 - 4 = 32
b = square root of 32
= 5.66ft
An equation which can be used to solve the given system of equations is 3x⁵ - 5x³ + 2x² - 10x + 4 = 4x⁴ + 6x³ - 11.
<u>Given the following data:</u>
y = 3x⁵ - 5x³ + 2x² - 10x + 4
y = 4x⁴ + 6x³ - 11
<h3>What is a system of equations?</h3>
A system of equations can be defined an algebraic equation that only has two (2) variables and can be solved simultaneoulsy.
Equating the given equations, we have:
y = y
3x⁵ - 5x³ + 2x² - 10x + 4 = 4x⁴ + 6x³ - 11
3x⁵ - 5x³ + 2x² - 10x + 4 - (4x⁴ + 6x³ - 11) = 0
3x⁵ - 5x³ + 2x² - 10x + 4 - 4x⁴ - 6x³ + 11 = 0
3x⁵ - 5x³ + 2x² - 10x + 4 - 4x⁴ - 6x³ + 11 = 0
3x⁵ - 4x⁴ - 11x³ + 2x² - 10x + 15 = 0
Read more on equations here: brainly.com/question/13170908
Answer:
48-20x=21
Step-by-step explanation:
So, we basically have to clear the fractions (get rid of the denominators)
Multiply everything by the LCM of 6 and 8 (24)
24(2)-24(5/6x)=24(7/8)
48-20x=21
Hope this helps!
