Answer:

Step-by-step explanation:
u = Initial velocity of baseball
= Angle of hit = 
x = Displacement in x direction = 400 ft
y = Displacement in y direction = 15 ft
= Height of hit = 2.5 ft
= g = Acceleration due to gravity = 
t = Time taken
Displacement in x direction

Displacement in y direction

The minimum initial velocity needed for the ball to clear the fence is 