A ball is thrown from an intial height of 5 feet with an intial upward velocity of 17 ft/s. The ball's height h in feet after t
seconds is given by the following.
h=5+17t-16t^2
Find all values of t for which the ball's height is 9 feet.
Round your answer(s) to the nearest hundredth.
1 answer:
Answer:
-16t²+17t+7=11
==>16t²-17t+4=0
Δ=17²-4*4*16=33
==>t= (17-√33)/32=0.351732... (s)≈0.35 (s)
or t=(17+√33)/32=0.710767 (s)≈0.71 (s)
Step-by-step explanation:
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