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alexira [117]
3 years ago
12

1. Write two different equations whose solutions are 5 .

Mathematics
1 answer:
vovangra [49]3 years ago
3 0
Two equations that have the solution 5:
3y = 2y + 5
2y - y = -3 + 8

To solve an equation is to isolate a variable and find its specific value.
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The temperature in Waterloo was − 5°C at sunrise. By noon the temperature had risen by 12 Celsius degrees. What was the temperat
allochka39001 [22]
The answer is 7° Celsius.
6 0
3 years ago
Read 2 more answers
Determine whether the improper integral converges or diverges, and find the value if it converges.
salantis [7]

Answer:

Integral will be diverging in nature

Step-by-step explanation:

We have given integral \int_{5}^{\infty}\frac{3}{2}x^2dx

Now after solving the integral

[\frac{3}{2}\frac{x^3}{3}] limit from 5 to infinite

So [\frac{3}{2}\frac{\infty^3}{3}]-[\frac{3}{2}\times \frac{5^3}{3}]=\infty

As after solving integral we got infinite value so integral will be diverging in nature

7 0
2 years ago
SHOW YOUR WORK, <br><br>PLEASE HELP!!!!!!!!!
Shkiper50 [21]
To find the inverse, we swap the variables y and x, then solve for the new y.

3a. y=\frac{3}{x-1}

Swapping the variables: x=\frac{3}{y-1}
Solving for y: x(y-1)=3 \\ y-1= \frac{3}{x} \\ y=1+\frac{3}{x}
The domain of this inverse is x ≠ 0.
3b. y=x^2-1

Swapping: x = y^2 - 1
Solving for y: y^2 = x + 1 \\ y = \sqrt{x+1}
The domain of this inverse is x ≥ -1.
3c. y=\sqrt[3]{\frac{x-7}{3}}
Swapping: x=\sqrt[3]{\frac{y-7}{3}}
Solving for y: x^3=\frac{y-7}{3} \\ y-7=3x^3 \\ y=3x^3+7
The domain of this inverse is all real numbers.
4a. y=\frac{3}{x-1}, y=1+\frac{3}{x}
y=\frac{3}{(1+\frac{3}{x})-1} \\ y=\frac{3}{(\frac{3}{x})} \\ y=x
y=1+\frac{3}{(\frac{3}{x-1})} \\ y = 1+(x-1) \\ y = x

4c. y=\sqrt[3]{\frac{x-7}{3}}, y=3x^3+7
y=\sqrt[3]{\frac{(3x^3+7)-7}{3}} \\ y=\sqrt[3]{\frac{3x^3}{3}} \\ y=\sqrt[3]{x^3} \\ y=x
y=3(\sqrt[3]{\frac{x-7}{3}})^3+7 \\ y = 3({\frac{x-7}{3}})+7 \\ y = (x-7)+7 \\ y=x



3 0
3 years ago
A new car is purchased for 18000 dollars. The value of the car depreciates at 13.5% per year. What will the value of the car be,
leonid [27]

Answer:

The value of car after 14 years is  $ 2,363.04

Step-by-step explanation:

Given as :

The price of new car = N = $ 18,000

The rate of depreciation of the value of the car = R = 13.5 % per year

Let The value of car after 14 years = $ x

The time period = 14 years

<u>Now, According to question</u>

The value of car after n years = initial value of car × (1-\dfrac{\textrm rate}{100})^{\textrm Time}

or, $ x = N × (1-\dfrac{\textrm R}{100})^{\textrm n}

or, $ x = $ 18,000 × (1-\dfrac{\textrm 13.5}{100})^{\textrm 14}

Or, $ x = $ 18,000 × (0.865)^{14}

∴  x = $ 18,000 × 0.13128

I.e x = $ 2,363.04

So, The value of car after 14 years =  x = $ 2,363.04

Hence The value of car after 14 years is  $ 2,363.04  Answer

8 0
3 years ago
True or false if a radius of a circle intersects a chord it is perpendicular to that chord
UkoKoshka [18]
It would be false





*Character limit fill ignore*
8 0
3 years ago
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