Answer:
201
Step-by-step explanation:
The answer would be A. When using Cramer's Rule to solve a system of equations, if the determinant of the coefficient matrix equals zero and neither numerator determinant is zero, then the system has infinite solutions. It would be hard finding this answer when we use the Cramer's Rule so instead we use the Gauss Elimination. Considering the equations:
x + y = 3 and <span>2x + 2y = 6
Determinant of the equations are </span>
<span>| 1 1 | </span>
<span>| 2 2 | = 0
</span>
the numerator determinants would be
<span>| 3 1 | . .| 1 3 | </span>
<span>| 6 2 | = | 2 6 | = 0.
Executing Gauss Elimination, any two numbers, whose sum is 3, would satisfy the given system. F</span>or instance (3, 0), <span>(2, 1) and (4, -1). Therefore, it would have infinitely many solutions. </span>
The greatest common factor would be 1 because you need to factor both 14 and 55 so factor 14 and you get 2 and 7 factor 55 you get 5 and 11 the the GCF has to be 1
I hope this is helpful
Answer:
Step-by-step explanation:
In vertex form, the equation is
y = a(x-h)^2 + k
So just read off the values!
