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777dan777 [17]
3 years ago
5

Write a situation in which positive and negative numbers are used to describe values that have opposite meaning. What does 0 rep

resent in this situation
Mathematics
1 answer:
mote1985 [20]3 years ago
8 0
This would be something like [5] or -[-5] which is absolute value (>.<)
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At a baseball training camp, a computer system plots the paths of balls hit during sessions at the batting cage and generates eq
notsponge [240]
Are we solving for h or t
7 0
2 years ago
A​ number, one-fifth of that​ number, and one-sixth of that number are added. the result is 82. what is the original​ number?
rusak2 [61]
X + .2x + .(1/6) x = 82
x = 60

5 0
3 years ago
An urn contains 3 red and 7 black balls. Players A and B take turns (A goes first) withdrawing balls from the urn consecutively.
andrey2020 [161]

Answer:

The probability that A selects the first red ball is 0.5833.

Step-by-step explanation:

Given : An urn contains 3 red and 7 black balls. Players A and B take turns (A goes first) withdrawing balls from the urn consecutively.

To find : What is the probability that A selects the first red ball?

Solution :

A wins if the first red ball is drawn 1st,3rd,5th or 7th.

A red ball drawn first, there are E(1)= ^9C_2 places in which the other 2 red balls can be placed.

A red ball drawn third, there are E(3)= ^7C_2 places in which the other 2 red balls can be placed.

A red ball drawn fifth, there are E(5)= ^5C_2 places in which the other 2 red balls can be placed.

A red ball drawn seventh, there are E(7)= ^3C_2 places in which the other 2 red balls can be placed.

The total number of total event is S= ^{10}C_3

The probability that A selects the first red ball is

P(A \text{wins})=\frac{(^9C_2)+(^7C_2)+(^5C_2)+(^3C_2)}{^{10}C_3}

P(A \text{wins})=\frac{36+21+10+3}{120}

P(A \text{wins})=\frac{70}{120}

P(A \text{wins})=0.5833

6 0
3 years ago
Helpppppppppppppppppppppppppp
Alona [7]
Answer:
3x^2 (y^5)^1/4 which is the first choice

Explanation:
The fourth root means that the bracket under has the root has a power of 1/4.
So, the given expression is:
(81 * x^8 * y^5)^1/4
Now, we will distribute the power as follows:
(81 * x^8 * y^5)^1/4 = (81)^1/4 * (x^8)^1/4 * (y^5)^1/4
                               = 3 * x^2 * y^5/4
This expression is equivalent to:
3x^2 (y^5)^1/4 which is the first choice

Hope this helps :)

8 0
3 years ago
How would a find a rule for this cubic function?
ELEN [110]
Hello here is a solution : 

3 0
3 years ago
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