Ask question

Ask question

All categories

3 years ago

6

At a local fitness center, members pay a $14 membership fee and $3 for each aerobics class. Nonmenbers pay $5 for each aerobics

class. For what humber or aerobics classes will the cost for members and nonmenbers be the same?

1 answer:

torisob [31]3 years ago

3 0

Fee for members: y = 14+ 3x
fee for nonmembers: y= 5x

to find the number of aerobics classes that will cost the same for 2, you set 2 equation equal to each other:
$14 + 3x = 5x \\ 14 = 2x \\ x = 7$

You might be interested in

White and black shapes are used in a game Some of the shapes are circles All the other shapes are squares The ratio of white to

PIT_PIT [208]

Answer:

The fraction of all shapes which are square in shape is $\frac{23}{32}$ .

Step-by-step explanation:

Given that , in a game , white and black shapes are used. Some of them are circle in shape and remains are square in shape.

The ratio of white to black shapes are 5:11.

Consider 5x= the number of shapes which are white in color.

11x= The number of shapes which are black in color.

There are (5x+11x)= 16x shapes in the game.

The white circle and white square are in the ratio 3:7.

The number of white square is

$=(\textrm{The number of white shape})\times (\frac{7}{3+7})$

$=(5x)\times (\frac{7}{10})$

$=\frac{7x}{2}$

The black circles and black square are in the ratio 3:8

The number of black square is

$=(\textrm{The number of black shape})\times (\frac{8}{3+8})$

$=(11x)\times (\frac{8}{11})$

=8x

Therefore the total number of shape which are square is

$=\frac{7x}{2}+8x$

$=\frac{7x+16x}{2}$

$=\frac{23x}{2}$

The fraction of all shape are square is

$=\frac{\textrm{shape in square}}{\textrm{Total number shape}}$

$=\frac{\frac{23x}{2}}{16x}$

$=\frac{23}{32}$

5 0

3 years ago

Find the difference 9x2-24x2

vovikov84 [41]

So, I'm assuming that the x represents multiplication...
Because multiplication has a higher precedence over addition, we'll multiply the numbers first:
18 + 48
Then we simply add:
66

6 0

3 years ago

Read 2 more answers

The length of each side of a regular pentagon is increased by 8 inches, so the perimeter is now 65 inches. What is the original

evablogger [386]

<em>Here</em> as the <em>Pentagon</em> is <em>regular</em> so it's <em>all sides</em> will be of <em>equal length</em> . And if we assume It's each side be<em> </em><em><u>s</u></em> , then it's perimeter is going to be <em>(s+s+s+s+s) = </em><em><u>5s</u></em>.And as here , each <em>side</em> is increased by <em>8 inches</em> and then it's perimeter is <em>65 inches</em> , so we got that it's side after increament is<em> (s+8) inches</em> and original length is <em>s inches </em>. And if it's each side is <em>(s+8) inches</em> , so it's perimeter will be <em>5(s+8)</em> and as it's equal to <em>65 inches</em> . So , <em><u>5(s+8) = 65</u></em>

${:\implies \quad \sf 5(s+8)=65}$

${:\implies \quad \sf 5s+5\times 8=65}$

${:\implies \quad \sf 5s+40=65}$

${:\implies \quad \sf 5s=65-40}$

${:\implies \quad \sf 5s=25}$

${:\implies \quad \sf s=\dfrac{25}{5}=5}$

${:\implies \quad \bf \therefore \quad \underline{\underline{s=5\:\: Inches}}}$

As we assumed the original side to be <em><u>s</u></em> .

<em>Hence, the original side's length 5 inches </em>

8 0

2 years ago

Need help with this one

steposvetlana [31]

Answer:

∠TRS = 40°

Step-by-step explanation:

∠UTS is an exterior angle of the triangle

The exterior angle of a triangle is equal to the sum of the 2 opposite interior angles, that is

∠UTS = ∠TRS + ∠RST

9x - 15 = 3x + 16 + x + 9

9x - 15 = 4x + 25 ( subtract 4x from both sides )

5x - 15 = 25 ( add 15 to both sides )

5x = 40 ( divide both sides by 5 )

x = 8

∠TRS = 3x + 16 = (3 × 8) + 16 = 24 + 16 = 40°

4 0

3 years ago

James and lena decide to share the cost of buying a car that costs $2500. If James agrees to pay $250 more than Lena, what is th

sesenic [268]

I believe it's $2250 since you just subtract.

4 0

3 years ago

Read 2 more answers