The sequence is an arithmetic sequence.
The explicit formula for the given sequence is: a_n = 64-12n
Further explanation:
In order to find if the given sequence is arithmetic or not, the common difference has to be checked. The common difference the the difference between two consecutive terms of an arithmetic sequence.
So,
40-52 = -12
28-40 = -12
16-28 = -12
The common difference is same i.e. d = -12 so the given sequence is arithmetic sequence.
Explicit formula for Arithmetic Sequence:
The general formula for arithmetic sequence is:
As we know
a_1 = 52
and
d = -12
Putting the values in general formula for arithmetic sequence
<u>Keywords:</u> Arithmetic Sequence, Recursive Formula
<u>Learn more about arithmetic sequence at:</u>
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Answer:
The given parameters are:
Circle X
Radius = r
Circle Y
Radius = s
Step-by-step explanation:
Answer:
No solution
Step-by-step explanation:
(2x-2)=2x+3
subtract 2x from each side and you get -2=3 which is not true
Answer:
(f + g)(x) = x² + 3x + 5
Step-by-step explanation:
There are two different functions f(x) and g(x) with domain the set of all real numbers and given by
f(x) = 3x + 5 and
g(x) = x²
Now, we have to find the function (f + g)(x) which is obtained by simple arithmetic addition of the two functions.
Therefore, (f + g)(x) = f(x) + g(x) = (3x + 5) + (x²) = x² + 3x + 5 (Answer)
Hello from MrBillDoesMath
Answer: + 4/7, 6 (13/14)
Discussion:
Let L be the larger of the two numbers and S the smaller of the two. Then the first sentence translates into this:
-6L - L = -4 =>
-7L = -4 => (divide both sides by -7)
L = - (-4)/(-7) = + 4/7 (*)
The second sentence translates to
2 (L + S) = 15 => (divide both sides by 2)
(L +S) = 15/2 => (subtract L from each side)
S = 15/2 - L = 15/2 - 4/7 (using (*) above)
So
S = 15*7/(2*7) - (4*2)/(7*2) (combine over common denominator of 14)
S = 105/14 - 8/14 = 97/14 = 6 13/14
Something is crazy here! While 2(L +S) = 15 -- check it out -- our larger number L ( =4/7) is actually smaller than the S number (6 13/14)! Maybe I should have called them Y and X, respectively, as you suggested!
Thank you,
Mr. B
