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Grace [21]
2 years ago
8

Help! how do I do this??

Mathematics
2 answers:
rosijanka [135]2 years ago
7 0

Answer:

15 ft

Step-by-step explanation:

Using sinus law

sin(A) /a = sin(B) /b = sin(C) /c

Where smale letters indicate the sides

For this question :

(sin(90)*12)/sin(53)=15

eduard2 years ago
3 0

Answer:

9.58

Step-by-step explanation:

Sin=opposite/hypotenuse

sin53=12/length of slide

Length of slide=12sin53

=9.58

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The ratio of the number of dolls Jacky had to the number of dolls Peter had was 5:2 but, after Jacky gave 15 dolls to Peter, the
sleet_krkn [62]

Answer:

70 dolls

Step-by-step explanation:

Hello!

The ratio is 5:2, which are division of  a whole. They can be represented as 5x and 2x.

Jacky has 5x dolls, and Peter has 2x dolls. They were equal after subtracting 15 dolls from 5x and adding them to 2x.

Equation:

  • 5x - 15 = 2x + 15

Solve:

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So Jacky has 5(10) dolls, or 50 dolls, and Peter has 2(10) or 20 dolls.

The total sum is 70 dolls.

4 0
2 years ago
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If $5,000,000 were invested at 4% interest compound continuously, how much will the investment be worth in 30 years?
Lerok [7]

If $5,000,000 is invested at 4% interest compounded continuously, the investment will be worth $16,215,000 in 30 years.


6 0
3 years ago
Passing through the coordinate (10,12) parallel to y=6
erastova [34]

Answer:

y = 12

Step-by-step explanation:

A line parallel to y = 6 is, like y = 6, horizontal.  Such a line passing through (10,12) is y = 12.


7 0
3 years ago
Suppose r(t)=costi+sintj+3tk represents the position of a particle on a helix, where z is the height of the particle above the g
Ilia_Sergeevich [38]

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b. The particle's velocity is obtained by differentiating its position function:

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\vec v\left(\dfrac{16}3\right)=-\sin\dfrac{16}3\,\vec\imath+\cos\dfrac{16}3\,\vec\jmath+3\,\vec k

c. The tangent to \vec r(t) at t=\frac{16}3 is

\vec T(t)=\vec r\left(\dfrac{16}3\right)+\vec v\left(\dfrac{16}3\right)t

4 0
2 years ago
How to write an equation in slope intercept form when given parametric form?
artcher [175]
Hello here is a solution : 

8 0
2 years ago
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