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Grace [21]
3 years ago
8

Help! how do I do this??

Mathematics
2 answers:
rosijanka [135]3 years ago
7 0

Answer:

15 ft

Step-by-step explanation:

Using sinus law

sin(A) /a = sin(B) /b = sin(C) /c

Where smale letters indicate the sides

For this question :

(sin(90)*12)/sin(53)=15

eduard3 years ago
3 0

Answer:

9.58

Step-by-step explanation:

Sin=opposite/hypotenuse

sin53=12/length of slide

Length of slide=12sin53

=9.58

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Jamaar helped in the community garden for 21/10 hours this week. that was 2 4/5 equal-length shifts, because jamaar stopped earl
DochEvi [55]

21/10 divided by 2 4/5 represents the time spent on a shift

<h3>How to determine what 21/10 divided by 2 4/5 represent in this situation?</h3>

The given parameters are

Time = 21/10

Shifts = 2 4/5

This means that:

21/10 divided by 2 4/5 represents:

Time/Shift

i.e. time per shift

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7 0
2 years ago
Asking for the equation
Novay_Z [31]

Answer:

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Step-by-step explanation:

7 0
3 years ago
Show that 3 · 4^n + 51 is divisible by 3 and 9 for all positive integers n.
-BARSIC- [3]

Answer:

Step-by-step explanation:

Hello, please consider the following.

3\cdot 4^n+51=3\cdot 4^n+3\cdot 17=3(4^n+17)

So this is divisible by 3.

Now, to prove that this is divisible by 9 = 3*3 we need to prove that

4^n+17 is divisible by 3. We will prove it by induction.

Step 1 - for n = 1

4+17=21= 3*7 this is true

Step 2 - we assume this is true for k so 4^k+17 is divisible by 3

and we check what happens for k+1

4^{k+1}+17=4\cdot 4^k+17=3\cdot 4^k + 4^k+17

3\cdot 4^k is divisible by 3 and

4^k+17 is divisible by 3, by induction hypothesis

So, the sum is divisible by 3.

Step 3 - Conclusion

We just prove that 4^n+17 is divisible by 3 for all positive integers n.

Thanks

4 0
3 years ago
Sophie found the volume of the figure below by using the steps shown.
Westkost [7]

Answer: it's C Sophie used the wrong height for the pyramid

It's Right cause I took the test.

Step-by-step explanation:

7 0
3 years ago
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Hello,

r= \dfrac{k}{w} \\&#10;\textrm{if w=10 then r=20} ==\ \textgreater \  20= \dfrac{k}{10} ==\ \textgreater \ k=200\\\\&#10;\textrm{if w=5 then }\\\\&#10;&#10;r= \dfrac{200}{5} =\boxed{40}
8 0
3 years ago
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