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san4es73 [151]
3 years ago
6

What type of printer heats toner to adhere it to the paper? inkjet . impact. 3D. laser.

Computers and Technology
1 answer:
Luden [163]3 years ago
8 0

Answer:

laser

Explanation:

These are well known printer types now.  Let's review how they work to determine in which does heat plays a role.

inkjet: inkjet printers are printer throwing ink at the paper in the form of little drops.  No heat involved here.

impact: That's the oldest technology, where a printing head is moving left and right to punch a printing ribbon and transfer ink onto the paper.  No heat involved.

3D: 3D printers don't usually use paper... as they use other materials to create a 3D representation of a model.  Heat is involved in the melting of the material before it's placed on the building model.  But no paper involved here.

laser: laser printers are working very much like a photocopier machine... memorizing the pattern to be printed, then transferring it onto paper... using heat.

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This question is for one of my classes I am in right now, and the question is:
suter [353]

Answer:

I will respond by saying the destination is not the most important , the journey is.

Explanation:

8 0
3 years ago
You do not need to use any functions beyond the main function in this problem. Initialize an array of int with the values: 4, 6,
zheka24 [161]

Answer:

import java.util.Scanner;

public class Main

{

public static void main(String[] args) {

   

    int[] arr = {4, 6, 9, 12};

    int sum = 0;

   

    for(int i=0; i<arr.length; i++){

        sum += arr[i];

    }

   

    for(int i=0; i<arr.length; i++){

        System.out.print(arr[i] + " ");

    }

    System.out.println("");

 System.out.println("The sum of the numbers: " + sum);

}

}

Explanation:

* The code is written in Java.

- Initialize the array with the given numbers

- Initialize the <em>sum</em> variable as zero

- Calculate the sum in the first for loop

- Print the numbers in the second for loop

- Print the <em>sum</em>

4 0
2 years ago
2(x-5)-3(3-x)=1/2(x-2)
lana [24]

you distribute and then combine like terms. x=4 :))

4 0
2 years ago
Hexadecimal to denary gcse method
Anuta_ua [19.1K]

There are two ways to convert from hexadecimal to denary gcse method. They are:

  • Conversion from hex to denary via binary.
  • The use of base 16 place-value columns.

<h3>How is the conversion done?</h3>

In Conversion from hex to denary via binary:

One has to Separate the hex digits to be able to know or find its equivalent in binary, and then the person will then put them back together.

Example - Find out the denary value of hex value 2D.

It will be:

2 = 0010

D = 1101

Put them them together and then you will have:

00101101

Which is known to be:

0 *128 + 0 * 64 + 1 *32 + 0 * 16 + 1 *8 + 1 *4 + 0 *2 + 1 *1

= 45 in denary form.

Learn more about hexadecimal from

brainly.com/question/11109762

#SPJ1

3 0
2 years ago
Assume that a gallon of paint covers about 350 square feet of wall space. Create anapplication with a main() method that prompts
Elena-2011 [213]

Answer:

import java.util.Scanner;

public class PaintClculator {

   public static void main(String[] args) {

Scanner in = new Scanner(System.in);

       System.out.println("Enter Values for length, width, and height of the room");

       double length = in.nextDouble();

       double width = in.nextDouble();

       double height = in.nextDouble();

       double wallArea = calculateWallArea(length,width,height);

       double noGallons = calculatePaint(wallArea);

       double price = price(noGallons);

       System.out.println("Price is: "+ price);

   }

   // Creating Method to Calculate Wall Area

   public static double calculateWallArea( double length, double width, double height){

       // formular for the surface area of a room Area=2*length*heigth+2*width*height+lenth*width

       double Area = 2*length*height+2*width*height+length*width;

       System.out.println("Wall Area: "+Area);

       return Area;

   }

   //Creating method to calculate amount of paint

   public static double calculatePaint(double Area){

       double noGallons = Area/350;

       System.out.println("Number of gallons: "+noGallons);

       return noGallons;

   }

   // Creating Method Calculate Price

   public static double price(double noGallons){

       return noGallons*32;

   }

}

Explanation

  1. Created Three Methods in all; calculateWallArea(), calculatePaint(), and price()
  2. Method calculateWallArea() calculates area based on this formula Area=2*length*heigth+2*width*height+lenth*width
  3. The value of Area is passed to method calculatePaint() Which calculates the number of gallons required to cover the area given that one gallon covers 350 wall space
  4. Method price() calculates and dis[plays the price by calling method calculatePaint() that returns number of gallons. since one gallon is 32$
3 0
3 years ago
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