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Karolina [17]
3 years ago
14

Use the given confidence interval limits to find the point estimate p^ and the margin of error E. 0.325

Mathematics
1 answer:
diamong [38]3 years ago
3 0

Answer:

0.350

Step-by-step explanation:

Confidence interval = point estimate ± margin of error

Point estimate = Confidence interval - margin of error

To get the margin of error, we will take the average of the difference of the interval given. Given the confidence interval 0.325<p<0.375

Margin of error = 0.375-0.325/2

Margin of error = 0.050/2

Margin of error = 0.025

Using the interval of 0.375

Point estimate = 0.375 - 0.025

Point estimate = 0.350

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there are 104 red candies in a candy machine. this represents 26% of the candy in the machine. how many total are in the candy m
Alborosie

There are 400 candies in the machine.

Step-by-step explanation:

Given,

Number of red candies in machine = 104

This represents 26% of the total candies.

Let,

x be the total candies in the machine.

According to statement;

26% of x = 104

\frac{26}{100}*x=104\\0.26x=104

Dividing both sides by 0.26

\frac{0.26x}{0.26}=\frac{104}{0.26}\\x=400

There are 400 candies in the machine.

Keywords: percentage, division

Learn more about percentages at:

  • brainly.com/question/317697
  • brainly.com/question/317616

#LearnwithBrainly

6 0
3 years ago
Select all expressions that represent a correct solution to the equation 6(x+4)=20
Sergeeva-Olga [200]

Answer:

D. 20 ÷ 6 − 4

E. 1/6(20 − 24)

F. (20−24) ÷ 6

Step-by-step explanation:

6(x + 4) = 20

6(x) + 6(4) = 20

6x + 24 = 20

     - 24  - 24

6x = -4

/6    /6

x = -4/6 or x = -2/3

D. 20 ÷ 6 − 4

20/6 - 4

20/6 - 24/6

-4/6 = -2/3

E. 1/6(20 − 24)

1/6(-4)

-4/6 = -2/3

F. (20 − 24) ÷ 6

- 4 / 6

-4/6 = -2/3

Hope this helps!

3 0
2 years ago
Write a percent that has a value between the two decimals 0.4 and 0.5
Juliette [100K]
A percent would be 0.45 
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3 years ago
Please help ..............
kherson [118]
The answer is 300 or 3*10^2
3 0
3 years ago
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The heights of women aged 20 to 29 are approximately normal with mean 64 inches and standard deviation 2.7 inches. men the same
Artyom0805 [142]
<span>To find the z-scores, find the difference in the number of inches for each value from the mean and then divide that by the standard deviation. For women at 72 inches (6'), this would be (72-64) / 2.7, or a z-score of +2.963. For a male at 72 inches, this would be (72-69.3)/2.8, or +0.964. This shows that the woman at 6 feet tall is more rare in the distribution than a man at 6 feet tall.</span>
5 0
3 years ago
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