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S_A_V [24]
3 years ago
6

Plz help first and correct answer will get brainiest thx and 5 stars ASAP

Mathematics
1 answer:
vaieri [72.5K]3 years ago
3 0

Answer:

A

Step-by-step explanation:

3/4x10=7  1/2so then you do 7 1/2 into improper and get 15/2 then subtract 7/2 and get 4

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stepladder [879]

I'm pretty sure its c I dont really understand stand what its asking

6 0
4 years ago
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Pls help quick will put brainliest
Olin [163]

Answer:

m<SQP=124°

Step-by-step explanation:

Hi there!

We're given ΔQRS, the measure of <R (90°), and the measure of <S (34°)

we need to find m<SQP (given as x+72°)

exterior angle theorem is a theorem that states that an exterior angle (an angle on the OUTSIDE of a shape) is equal to the sum of the two remote interior angles (the angle OUTSIDE of a shape will be equal to the sum of 2 angles that are OPPOSITE to that angle).

that means that m<SQP=m<R+m<S (Exterior angle theorem)

substitute the known values into the equation

x+72°=90°+34° (substitution)

combine like terms on both sides

x+72°=124° (algebra)

subtract 72 from both sides

x=52° (algebra)

however, that's just the value of x. Because m<SQP is x+72°, add 52 and 72 together to get the value of m<SQP

m<SQP=x+72°=52°+72°=124° (substitution, algebra)

Hope this helps!

4 0
3 years ago
Find the slope and reduce.<br> P=(-3, -4) Q=(5, -1)<br> ?<br> Slope =<br> Enter
arsen [322]

Answer:

Slope is 3/8

Step-by-step explanation:

( -1 + 4)/ (5 + 3)

3/ 8

8 0
4 years ago
What is x? I will give brainliest if you explain your answer.
horsena [70]

Answer:

  • x =  {0, π/2, 3π/2, 2π}

Step-by-step explanation:

  • cotx cos x - cot x = 0
  • cotx( cosx - 1) = 0

1. <u>cotx = 0</u>

  • x = π/2 + πn
  • In the interval [0, 2π] we have π/2 and 3π/2

2. <u>cosx = 1</u>

  • x  = 0 + 2πn
  • In the given interval we have 0 and 2π

<u>So the solution set is:</u>

  • x =  {0, π/2, 3π/2, 2π}

3 0
3 years ago
Verify that the following equation is an identity. (1/sinx) - (1/cscx) = cscx - sinx
Anarel [89]
Manipulating the left side of the equation, we obtain:

\dfrac{1}{\sin x}-\dfrac{1}{\csc x}=\dfrac{\csc x-\sin x}{\sin x\cdot\csc x}

Using that \csc x=\dfrac{1}{\sin x}:

\dfrac{\csc x-\sin x}{\sin x\cdot\csc x}=\dfrac{\csc x-\sin x}{\sin x\cdot\dfrac{1}{\sin x}}=\dfrac{\csc x-\sin x}{1}=\csc x-\sin x\\\\\boxed{\dfrac{1}{\sin x}-\dfrac{1}{\csc x}=\csc x-\sin x}~~\blacksquare
6 0
3 years ago
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