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Vitek1552 [10]
3 years ago
9

Who has done the k12 test on math if so and mad a 100% please give me the answers

Mathematics
1 answer:
e-lub [12.9K]3 years ago
4 0

Answer:

Where's the image of the surfaces?

Step-by-step explanation:

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Please help me!! Thanks!
nikdorinn [45]

Answer: $30 and 1 cent more

$60.50 - $30.50 = $30

0.12 - 0.11 = 0.01

I hope this helps.

5 0
3 years ago
You have a 25 cm piece of ribbon. How many cuts do you need to make obtain the greatest number of pieces, where each piece is di
max2010maxim [7]

Answer:

24

Step-by-step explanation

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7 0
2 years ago
Read 2 more answers
I have 100 items of product in stock. The probability mass function for the product's demand D is P(D=90)=P(D=100)=P(D=110)=1/3.
masya89 [10]

Answer:

The probability mass function for the items sold is

P_X(k) = \left \{ {\frac{1}{3} \, \, \, {k=90} \atop \, \frac{2}{3} \, \, \, {k=100}} \right.

The mean is 96.667

The variance is 22.222

b) The probability mass function for the unfilled demand due to lack of stock is

P_Y(k) = \left \{ {\frac{2}{3} \, \, \, {k=0} \atop \, \frac{1}{3} \, \, \, {k=10}} \right.

The mean is 3.333

The variance is 33.333

Step-by-step explanation:

If the demand is higher than 100, then you will sell 100 items only. Thus, there is a probability of 1/3+1/3 = 2/3 that you will sell 100 items, while there is a probability of 1/3 that you will sell 90.

The probability mass function for the items sold is

P_X(k) = \left \{ {\frac{1}{3} \, \, \, {k=90} \atop \, \frac{2}{3} \, \, \, {k=100}} \right.

The mean is 1/3 * 90 + 2/3 * 100 = 290/3 = 96.667

The variance is V(X) = E(X²)-E(X)² = (1/3*90² + 2/3*100²) - (290/3)² = 200/9 = 22.222

b) If order to be unfilled demand, you need to have a demand of 110, which happens with probability 1/3. In that case, the value of the variable, lets call it Y, that counts the amount of unfilled demand due to lack of stock is 110-100 = 10. In any other case, the value of Y is 0, which would happen with probability 1-1/3 = 2/3. Thus

P_Y(k) = \left \{ {\frac{2}{3} \, \, \, {k=0} \atop \, \frac{1}{3} \, \, \, {k=10}} \right.

The mean is 2/3 * 0 + 1/3 * 10 = 10/3 = 3.333

The variance is 2/3*0² + 1/3*10² = 100/3 = 33.333

4 0
3 years ago
Help me with number one and number six before answering say which number you are answering please help me and thank you.
Ksenya-84 [330]
1) 3 times 15 is 45
6) because in order for it to even have a slope it has to be constant through out the whole thing.
5 0
3 years ago
Help me yall this for me aint it.
aleksandrvk [35]

Answer:

20(4 + 5)

Step-by-step explanation:

GCF is just the biggest number each value can be divided by. Here, it's 20, so that goes outside of the parenthesis. Now, what can you multiply by 20 to get 80? 4, so that goes in the second box. What can you multiply by 20 to get 100? 5, so that goes in the last box. You can check your answer by doing 80 + 100 = 180; 20(9) = 180.

6 0
3 years ago
Read 2 more answers
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