To get the *percent increase* from week 1 to week 2, we calculate the change in distance from week 1 to week 2 (13.5 - 12.5 = 1 mile) over the week 1 distance (12.5 miles). Doing that, we find that Matthew increased his distance by
1/12.5 = 0.08, or 8%
We’re given that he’ll increase his distance by the same percentage from week 2 to 3, so to find his week 3 distance, we can find 8% of the week 2 distance and add that on. 8% of 13.5 miles is 0.08 x 13.5 = 1.08 miles, so by week 3, he’ll be running 13.5 + 1.08 = 14.58 miles.
Answer:
d = 14/5
Step-by-step explanation:
The point (-4,2) means that;
At x = -4, y = 2
Now general form of a linear equation is;
Ax + By + C = 0
We are given;
4y = 3x + 6
Rearranging to the form of a linear equation gives;
3x - 4y + 6 = 0
Thus, A = 3, B = -4 and C = 6
Thus, at point (-4,2), distance between them is;
d = (3(-4) - 4(2) + 6)/√(3² + (-4)²)
d = -14/5
We will take the absolute value.
Thus; d = 14/5
Answer:
Mean: 5
Median: 5
Mode: 2
Range: 7
Step-by-step explanation:
We find the mean by adding all the numbers together to get 45. Then we divide the 45 by the amount of numbers in the set, for this one it is 9. 45 divided by 9 equals 5.
To find the median we put the numbers in the set in order from least to greatest. Next, we find the middle number. median=5
To find the mode we find the number repeated the most. In this set the number that repeats the most is 2.
Range is found by subtracting the largest number and the smallest number. 9-2=7
Answer:
x = 4
Step-by-step explanation:
9(x - 2) = 18
9x - 18 = 18
9x = 18 + 18
9x = 36
x = 36/9
x = 4
Answer:
10.8 minutes
Step-by-step explanation:
Given data
We are told that the number of Jugs is 18
Filling the first 3 jugs has taken 5 minutes
let us find the filling rate
Rate= 3/5
Rate= 0.6 Jugs per minute
Hence the rate of filling is 0.6 Jugs per minute
Therefore the time take to fill the remaining 16 jugs is
TIme= Rate*Number of Jugs
TIme= 0.6*18
Time= 10.8 minutes
