1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Nina [5.8K]
3 years ago
14

How do I type in exponents

Mathematics
1 answer:
defon3 years ago
8 0

Answer:

on what

Step-by-step explanation: normaly you have a button that you can have certain characters

You might be interested in
Help plz if your good at finding the area of the compound figure plz help if you don’t know the answer your not needed but if yo
spin [16.1K]

Answer:

96cm^2

Step-by-step explanation:

We can divide it into two rectangles: 7x8 and 10x(12-8), arriving at the solution of 7cm*8cm + 10cm*4cm = 56cm^2 + 40cm^2 = 96cm^2

We can also divide it into two rectangles: 12x7 + (12-8)x(10-7), arriving at 12cm*7cm + 4cm*3cm = 84cm^2 + 12cm^2 = 96cm^2

We could also divide it to one big rectangle and one "negative" rectangle of 10x12 and -8x(10-7), arriving at 10cm*12cm - 8cm*3cm = 120cm^2 - 24cm^2 = 96cm^2

6 0
3 years ago
The two triangles are similar. What is the value of x? Enter your answer in the box.
ra1l [238]

Just took the test and got the the correct answer *\(♡°▽°♡)/*

Look at the image down below!!


5 0
3 years ago
Read 2 more answers
Indicate the equation of the given line in standard form. The line through the midpoint of and perpendicular to the segment join
lianna [129]
The midpoint is (3,-1) 

5 0
3 years ago
A triangle has angles in the ratio 3:10:2 what is the size of the largest angle x?
Annette [7]

Answer:

B

Step-by-step explanation:

let the angles be 3k,10k,2k

then 3k+10k+2k=180

15k=180

k=180/15=12

x=10k=10×12=120°

5 0
4 years ago
Which is the approximate solution to the system y = 0.5x + 3.5 and y = − 2/3 x + 1/3 shown on the graph? (–2.7, 2.1) (–2.1, 2.7)
AlekseyPX

Answer:

The approximate solution to the system is (-2.7, 2.1).

Step-by-step explanation:

To solve the system of equations \begin{bmatrix}y=0.5x+3.5\\ y=-\frac{2}{3}x+\frac{1}{3}\end{bmatrix} you must:

\mathrm{Rationalize\:equations}\\\\\begin{bmatrix}y=\left(\frac{1}{2}\right)x+\left(\frac{7}{2}\right)\\ y=-\frac{2}{3}x+\frac{1}{3}\end{bmatrix}

\mathrm{Subsititute\:}y=-\frac{2}{3}x+\frac{1}{3}\\\\\begin{bmatrix}-\frac{2}{3}x+\frac{1}{3}=\frac{1}{2}x+\frac{7}{2}\end{bmatrix}

\mathrm{Isolate}\:x\:\mathrm{for}\:-\frac{2}{3}x+\frac{1}{3}=\frac{1}{2}x+\frac{7}{2}\\\\-\frac{2}{3}x=\frac{19}{6}+\frac{1}{2}x\\\\-\frac{7}{6}x=\frac{19}{6}\\\\6\left(-\frac{7}{6}x\right)=\frac{19\cdot \:6}{6}\\\\-7x=19\\\\x=-\frac{19}{7}\approx-2.7

\mathrm{For\:}y=-\frac{2}{3}x+\frac{1}{3}\\\\\mathrm{Subsititute\:}x=-\frac{19}{7}\\\\y=-\frac{2}{3}\left(-\frac{19}{7}\right)+\frac{1}{3}\\\\y=\frac{15}{7}\approx 2.1

The approximate solutions to the system of equations are:

x=-2.7 ,\:y=2.1

5 0
3 years ago
Read 2 more answers
Other questions:
  • PLEASE HELP! I’ll GIVE THE BRAINLIEST TO WHOEVER ANSWERS CORRECTLY!!
    15·1 answer
  • Alma reasoned that adding a rational number with an irrational number would give you a rational number. is alma correct? explain
    15·2 answers
  • Solve the equation algebraically x^2=180
    12·1 answer
  • Gabby purchased a pair of ear phones online for $12. She purchased the ear phones at 60% of the store price. What was the store
    11·1 answer
  • I need help (40pts)I will give brainliest & I put the screenshot of question
    6·1 answer
  • Of 1,050 randomly selected adults, 360 identified themselves as manual laborers, 280 identified themselves as non-manual wage ea
    14·1 answer
  • 0645 + 0745 answer in military time
    14·1 answer
  • Kelsey must pay $200 to rent a booth at the craft fair. The materials for each pendant cost $7.80, and she plans to sell each pe
    9·2 answers
  • I will give Brainliest
    11·2 answers
  • I need help with Geometry
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!