Answer:
9r+13
Step-by-step explanation:
To solve this question, all we need to do is simplify the equation.
The equation is 8r+7+4+r. To simplify, we need to add like terms.
8r+r+7+4=9r+13
9r+13 is the equivalent equation to 8r+7+4+r.
Hope this helps!
Answer:
6 (19 x - 2)
Step-by-step explanation:
Simplify the following:
6 - 3 (4 - 3 x) - 3 x - 6×9 x + 18×9 x - 6
-6×9 = -54:
6 - 3 (4 - 3 x) - 3 x + -54 x + 18×9 x - 6
18×9 = 162:
6 - 3 (4 - 3 x) - 3 x - 54 x + 162 x - 6
Grouping like terms, 6 - 3 (4 - 3 x) - 3 x - 54 x + 162 x - 6 = (-3 x - 54 x + 162 x) - 3 (4 - 3 x) + (6 - 6):
(-3 x - 54 x + 162 x) - 3 (4 - 3 x) + (6 - 6)
-3 x - 54 x + 162 x = 105 x:
105 x - 3 (4 - 3 x) + (6 - 6)
6 - 6 = 0:
105 x - 3 (4 - 3 x)
-3 (4 - 3 x) = 9 x - 12:
9 x - 12 + 105 x
Grouping like terms, 105 x + 9 x - 12 = (105 x + 9 x) - 12:
(105 x + 9 x) - 12
105 x + 9 x = 114 x:
114 x - 12
Factor 6 out of 114 x - 12:
Answer: 6 (19 x - 2)
he elements of the Klein <span>44</span>-group sitting inside <span><span>A4</span><span>A4</span></span> are precisely the identity, and all elements of <span><span>A4</span><span>A4</span></span>of the form <span><span>(ij)(kℓ)</span><span>(ij)(kℓ)</span></span> (the product of two disjoint transpositions).
Since conjugation in <span><span>Sn</span><span>Sn</span></span> (and therefore in <span><span>An</span><span>An</span></span>) does not change the cycle structure, it follows that this subgroup is a union of conjugacy classes, and therefore is normal.
Answer:
B
Step-by-step explanation:
<u>Answer:</u>
The Kinetic energy of the 110 kg linebacker is 1375 J
<u>Solution:</u>
The kinetic energy of an object is the energy produced by its velocity. Kinetic energy of an object is directly proportional to the mass and the square of the its velocity.
Therefore, the formula for kinetic energy is
Here, The linebacker’s mass m = 110 kg
The linebacker’s velocity v = 5 m/s
So by substituting the values,
The kinetic energy of linebacker is
