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umka2103 [35]
3 years ago
5

Prove that (Cosx-Cos³x)/Sinx=SinxCosx​

Mathematics
1 answer:
77julia77 [94]3 years ago
4 0

Answer:

(Cosx-Cos³x)/Sinx=SinxCosx

Step-by-step explanation:

sin3x−cos3x

=sinxsin2x−cosxcos2x

=sinx(1−cos2x)−cosx(1−sin2x)

=sinx−sinxcos2x−cosx+cosxsin2x

=sinx−cosx+(sinx−cosx)sinxcosx  

=(sinx−cosx)(1+sinxcosx

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F(22) = 2(22 + 6)    Use the Distributive Property
F(22) = 44 + 12       Add
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3 years ago
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Secants BE and CF intersect at point D inside A. What is the measure of CDE?
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answer
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