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umka2103 [35]
3 years ago
5

Prove that (Cosx-Cos³x)/Sinx=SinxCosx​

Mathematics
1 answer:
77julia77 [94]3 years ago
4 0

Answer:

(Cosx-Cos³x)/Sinx=SinxCosx

Step-by-step explanation:

sin3x−cos3x

=sinxsin2x−cosxcos2x

=sinx(1−cos2x)−cosx(1−sin2x)

=sinx−sinxcos2x−cosx+cosxsin2x

=sinx−cosx+(sinx−cosx)sinxcosx  

=(sinx−cosx)(1+sinxcosx

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Evaluate the limit 12n^3 - 2n^2 + 9 / 4n^3
geniusboy [140]

Answer:

3

Step-by-step explanation:

Evaluate the limit n - > ∞ 12n^3 - 2n^2 + 9 / 4n^3

Divide the expression by the highest power of n to have

limit n - > ∞ 12n³/n³ - 2n²/n³ + 9/n³ / 4n³/n³

= limit n -  > ∞12 - 2/n + 9/n³ / 4

Substitute the value of n

= 12 - 2/∞ + 9/∞³ / 4

Since a/∞ = 0

The expression becomes;

= 12 - 0+ 0/4

= 12/4

= 3

Hence the required limit is 3

7 0
3 years ago
Multiply and simplify .<br> b^4•b•b^2•b^3<br> B^9<br> 4b^9<br> B^10<br> B^24
tino4ka555 [31]

Use Product Rule: x^a b^a = x^a + b

b^4 + 1 + 2 + 3

Simplify 4 + 1 + 2 + 3 to 10

Answer: B^10

6 0
3 years ago
The least common multiple of 2, 5, 6, and 9 is<br><br> A. 60.<br> B. 45.<br> C. 90.<br> D. 180.
ankoles [38]
The least common multiple between those following numbers is C. 90.
5 0
3 years ago
Read 2 more answers
An auto mechanic converts a metric part to 0.492 in. The part comes only in fractional sizes given to the nearest 64th of an inc
tatuchka [14]

Answer:

the closest part the mechanic can chose is 0.5 inch

Step-by-step explanation:

fractional sizes given to the nearest 64th of an inch = 1/64 = 0.0156

the closest size to 0.492in = 0.492 + 0.0156 = 0.5076 inches

approximately, the closest part the mechanic can chose is 0.5 inch

4 0
3 years ago
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viva [34]
The answer is
3 divided by 2
Hope this helped
5 0
2 years ago
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