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umka2103 [35]
3 years ago
5

Prove that (Cosx-Cos³x)/Sinx=SinxCosx​

Mathematics
1 answer:
77julia77 [94]3 years ago
4 0

Answer:

(Cosx-Cos³x)/Sinx=SinxCosx

Step-by-step explanation:

sin3x−cos3x

=sinxsin2x−cosxcos2x

=sinx(1−cos2x)−cosx(1−sin2x)

=sinx−sinxcos2x−cosx+cosxsin2x

=sinx−cosx+(sinx−cosx)sinxcosx  

=(sinx−cosx)(1+sinxcosx

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inna [77]

10. tan(30) = l / 6√3

l = tan(30) x 6√3

l = 6

cos(30) = 6√3 / y

y =  6√3/cos(30)

y = 12

11. tan(30) = c/30

c = 30 x tan(30)

c = 10√3

cos(30) = 27/w

w = 27/cos(30)

w = 18√3

12.

sin(60) = 36/y

y = 36/sin(60)

y = 24√3

tan(60) = 36/x

x = 36/tan(60)

x = 12√3

7 0
3 years ago
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4 years ago
What is the answer to this equation. Please I really need help.
Anika [276]

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Angle A = Angle X

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Step-by-step explanation:

Both triangles are stated to be equal so we can draw two triangles and label them. One triangle has Point A, Point B, and Point C. The second triangle has Point X, Point Y, and Point Z. Make sure that Point X on the second triangle is in the same spot as Point A on the first triangle (same for points B, C, Y, and Z).

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