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LenKa [72]
3 years ago
12

If a sum of several numbers is odd, then at least one of the numbers is itself odd.

Mathematics
1 answer:
labwork [276]3 years ago
4 0

Answer with Step-by-step explanation:

We are given that if sum of several numbers is odd

We have to prove that at least one of the number is itself odd.

Suppose, we have three numbers

a=6 , b=7,d=8

Sum of numbers=6+7+8=21=Odd number

We know that sum of two odd numbers is always an even number.

Sum of an odd number and an even number is always an odd number.

If we take even odd numbers then sum is always an even number and sum of odd odd numbers then the sum is always an odd number.

7+5+3=15

7+3+9+5=24

Sum of even numbers is always an even number.

Hence, there are atleast one numebr is odd then the sum of several number is odd.

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Can anyone help me with this
Nataliya [291]
To find surface area, we can use the equation:

SA=2lw+2wh+2lh, where:
l=10 in
w=3 in
h=7 in

SA=(2)(10)(3)+(2)(3)(7)+(2)(10)(7)
SA=60+42+140
SA=242 in²
5 0
3 years ago
Limit of x^2-81/x+9<br> As x goes toward -9
Semmy [17]
Hello,

Use the factoration

a^2 - b^2 = (a - b)(a + b)

Then,

x^2 - 81 = x^2 - 9^2

x^2 - 9^2 = ( x - 9).(x + 9)

Then,

Lim (x^2- 81) /(x+9)

= Lim (x -9)(x+9)/(x+9)

Simplity x + 9

Lim (x -9)

Now replace x = -9

Lim ( -9 -9)

Lim -18 = -18
_______________

The second method without using factorization would be to calculate the limit by the hospital rule.

Lim f(x)/g(x) = lim f(x)'/g(x)'

Where,

f(x)' and g(x)' are the derivates.

Let f(x) = x^2 -81

f(x)' = 2x + 0
f(x)' = 2x

Let g(x) = x +9

g(x)' = 1 + 0
g(x)' = 1

Then the Lim stay:

Lim (x^2 -81)/(x+9) = Lim 2x /1

Now replace x = -9

Lim 2×-9 = Lim -18

= -18




7 0
3 years ago
Write the simplest polynomial function with the given roots 2i, square root of 3, and 4
Volgvan

Answer:

  • y = (x - 4)(x + 2i)(x - 2i)(x + √3)(x - √3) Possible answer
  • y = (x - 4)(x^2 + 4)(x^2 - 3)                    Possible answer

Step-by-step explanation:

The simplest answer is that 2i cannot be a lone root. It must have a twin that is - 2i

√3 has the same sort of rule. It cannot be a root all by itself. It also must have a twin, in this case -√3

So the answer must be

(x - 4)(x + 2i)(x - 2i)(x + √3)(x - √3)      <<< Possible answer

but this can be reduced even further.

  • (x + 2i)(x - 2i) = x^2 - x*2i + x*2i - 4i^2
  • (x + 2i)(x - 2i) = x^2 - 4(i)^2
  • (x + 2i)(x - 2i) = x^2  + 4.               Remember i^2 = - 1

By a similar method (x - √3)(x + √3) = x^2 - 3

So the polynomial is reduced to

(x - 4)(x^2 + 4)(x^2 - 3)  <<<< Answer

If this is not among your answers and the  factored form is not either, please tell me what is.

5 0
3 years ago
True or False? A circle could be circumscribed about the quadrilateral below.
SVEN [57.7K]

Answer:

<em>The correct answer is:   False</em>

Step-by-step explanation:

<u>If the sum of the opposite angles in a quadrilateral is 180°</u>, then a circle can be circumscribed about the quadrilateral.

Here,  \angle B+\angle D= 110\°+90\° = 180\°

but,  \angle A+\angle C= 70\°+90\°= 160\°

So, a circle can't be circumscribed about the given quadrilateral.

7 0
3 years ago
Read 2 more answers
I needed help on this
Strike441 [17]

Answer:

Step-by-step explanation:

Let Freda's sum = x

Donnie has 3/4 x

He spends 63 dollars. His sum is now

3/4x - 63

Now the equation looks like this

6(3/4x - 63) = x            Remove the brackets

6*3/4 x - 378 =x

6 * 3/4 = 4 1/2

4 1/2 x - 378 = x           Add 378 to both sides

4 1/2 x = x + 378          Subtract x from both sides

3.5 x = 378                  Divide by 3.5

x = 378 /3.5

x = 108

Since x = 108, that's how much Freda had. (She spent nothing).

5 0
3 years ago
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