If a sum of several numbers is odd, then at least one of the numbers is itself odd.
1 answer:
Answer with Step-by-step explanation:
We are given that if sum of several numbers is odd
We have to prove that at least one of the number is itself odd.
Suppose, we have three numbers
a=6 , b=7,d=8
Sum of numbers=6+7+8=21=Odd number
We know that sum of two odd numbers is always an even number.
Sum of an odd number and an even number is always an odd number.
If we take even odd numbers then sum is always an even number and sum of odd odd numbers then the sum is always an odd number.
Sum of even numbers is always an even number.
Hence, there are atleast one numebr is odd then the sum of several number is odd.
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The two linear equations in two variable is:
12 x + 3 y = 40
7 x - 4 y = 38
(a) For a system of equations in two Variable
a x + by = c
p x + q y = r
It will have unique solution , when
As, you can see that in the two equation Provided above
So, we can say the system of equation given here has unique solution.
(b). If point (2.5, -3.4) satisfies both the equations, then it will be solution of the system of equation, otherwise not.
1. 12 x+3 y=40
2. 7 x-4 y=38
Substituting , x= 2.5 , and y= -3.4 in equation (1) and (2),
L.H.S of Equation (1)= 1 2 × 2.5 + 3 × (-3.4)
= 30 -10.20
= 19.80≠ R.H.S that is 40.
Similarly, L H S of equation (2)= 7 × (2.5) - 4 × (-3.4)
= 17.5 +13.6
= 31.1≠R HS that is 38
So, you can Write with 100 % confidence that point (2.5, -3.4) is not a solution of this system of the equation.
Answer:
Option E) 61.6
Step-by-step explanation:
We are given the following information in the question:
Mean, μ = 100 bushels per acre
Standard Deviation, σ = 30 bushels per acre
We assume that the distribution of yield is a bell shaped distribution that is a normal distribution.
Formula:
P(X>x) = 0.90
We have to find the value of x such that the probability is 0.90
P(X > x)
Calculation the value from standard normal table, we have,
Hence, the yield of 61.6 bushels per acre or more would save the seed.