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2 years ago

(2x + 3y) + (4x - 3y) = 11+(-5)

Mathematics

1 answer:

Maurinko [17]2 years ago

3 0

Answer:

The correct option should have been $6x=6$ .

Step-by-step explanation:

Given the expression

$\left(2x\:+\:3y\right)\:+\:\left(4x\:-\:3y\right)\:=\:11+\left(-5\right)$

solving the expression

$\left(2x\:+\:3y\right)\:+\:\left(4x\:-\:3y\right)\:=\:11+\left(-5\right)$

Remove parentheses: (a) = a

$2x+3y+4x-3y=11-5$

Group like terms

$3y-3y+2x+4x=11-5$

Add similar elements

$6x=6$

It is clear that not a single given option is $6x=6$ . It means no option is correct. It seems you mistyped the correct options.

The correct option should have been $6x=6$ .

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2 years ago

Point Q is plotted on the coordinate grid. Point P is at (40, −20). Point R is vertically above point Q. It is at the same dista

lara31 [8.8K]

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$\displaystyle d_{RP}=50\sqrt{2}\ units$

Step-by-step explanation:

Distance between points in $R^2$

If P(p1,p2) and Q(q1,q2) are points on the plane $R^2$ , the distance between them is

$\displaystyle d=\sqrt{(q_1-p_1)^2+(q_2-p_2)^2}$

We have Q(-10,-20) plotted on the coordinate grid. We also know that P is at (40, -20). We can see they have the same y-coordinate, so the distance between them is computed simply by subtracting their x-coordinates

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The point R is located at (-10,30)

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$\displaystyle d_{RP}=\sqrt{5000}$

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