In complex calculations like this, the precedence goes like this

B = Brackets
O = Of (or Exponent)
D = Division
M = Multiplication
A = Addition
S = Substraction

So, in your formula, it will go like this

1/2x3+1/4x2
= 0.5 x 3 + 0.25 x 2
= 1.5 + 0.5
= 2

Hope this helps.

4 0

3 years ago

A type of bacteria has a very high exponential growth rate of 80% every hour. If there are 10 bacteria, determine how many will

Lana71 [14]

<h3>There are 189 bacteria in 5 hours</h3><h3>There are 13382588 bacteria in 1 day</h3><h3>There are $10(1.8)^{168}$ bacteria in 1 week</h3>

<em><u>Solution:</u></em>

Given that,

A type of bacteria has a very high exponential growth rate of 80% every hour

There are 10 bacteria

<em><u>The increasing function is given as:</u></em>

$y = a(1+r)^t$

Where,

y is future value

a is initial value

r is growth rate

t is time period

From given,

a = 10

$r = 80 \5 = \frac{80}{100} = 0.8$

<em><u>Determine how many will be in 5 hours</u></em>

Substitute t = 5

$y = 10(1 + 0.8)^5\\\\y = 10(1.8)^5\\\\y = 10 \times 18.89568\\\\y \approx 188.96$

y = 189

Thus, there are 189 bacteria in 5 hours

<em><u>Determine how many will be in 1 day ?</u></em>

1 day = 24 hours

Substitute t = 24

$y = 10(1 + 0.8)^{24}\\\\y = 10(1.8)^{24}\\\\y = 10 \times 1338258.84\\\\y = 13382588.45\\\\y \approx 13382588$

Thus, there are 13382588 bacteria in 1 day

<em><u>Determine how many will be in 1 week</u></em>

1 week = 168

Substitute t = 168

$y = 10(1 + 0.8)^{168}\\\\y = 10(1.8)^{168}$

Thus there are $10(1.8)^{168}$ bacteria in 1 week

6 0

3 years ago