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Hunter-Best [27]
2 years ago
14

Please can you give me help with answers. Thanks

Mathematics
1 answer:
Margaret [11]2 years ago
5 0
1) 110+30+a = 180
a = 180-140 = 40
Obtuse angled triangle

2) 50+50+C = 180
C=180-100 =80
Acute angled triangle

3) 45+45+b =180
b =180-90 = 90 
Right angled triangle

4) 45+60+C = 180
C = 180-105 =75 
Acute angled triangle

5) 94+47+b =180
b = 180-141=39

Obtuse angled triangle

6)81+53+a = 180
a =180-134 = 46

Acute angled triangle

7) 38+45+b =180
b = 180-83 =97
Obtuse angled triangle

8) 36+54+C =180
C =180-90 = 90

Right angled triangle.
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What is the difference between bernoulii equation and riccati equation
melisa1 [442]
The Bernoulli equation is almost identical to the standard linear ODE.

y'=P(x)y+Q(x)y^n

Compare to the basic linear ODE,

y'=P(x)y+Q(x)

Meanwhile, the Riccati equation takes the form

y'=P(x)+Q(x)y+R(x)y^2

which in special cases is of Bernoulli type if P(x)=0, and linear if R(x)=0. But in general each type takes a different method to solve. From now on, I'll abbreviate the coefficient functions as P,Q,R for brevity.

For Bernoulli equations, the standard approach is to write

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The Riccati equation, on the other hand, requires a different substitution. Set v=Ry, so that v'=R'y+Ry'=R'\dfrac vR+Ry'. Then you have

y'=P+Qy+Ry^2
\dfrac{v'-R'\dfrac vR}R=P+Q\dfrac vR+R\dfrac{v^2}{R^2}
v'=PR+\left(Q+\dfrac{R'}R\right)v+v^2

Next, setting v=\dfrac{u'}u, so that v'=\dfrac{uu''-(u')^2}{u^2}, allows you to write this as a linear second-order equation. You have

\dfrac{uu''-(u')^2}{u^2}=PR+\left(Q+\dfrac{R'}R\right)\dfrac{u'}u+\dfrac{(u')^2}{u^2}
u''-\left(Q+\dfrac{R'}R\right)u'+PRu=0
u''+Su'+Tu=0

where S=-\left(Q+\dfrac{R'}R\right) and T=PR.
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