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2 years ago

6

Geometry help needed. more information in the picture. please help. would be greatly appreciated.

1 answer:

ratelena [41]2 years ago

4 0

Answer:

60

Step-by-step explanation:

180-120=60so the answer is a 60

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Which values of m and b will create a system of equations with no solution? Check all that apply. y = mx + b y = –2x + 3/2

Leni [432]

Lines with no solution are parallel lines....parallel lines will contain the same slope, but different y intercepts.

y = -2x + 3/2....slope (m) = -2 and y int (b) = 3/2
so the line we need will have a slope of -2, but can have any y int EXCEPT 3/2.

m = -2, and b = -1/3 is parallel, no solution
m = -2 and b = -2/3...parallel, no solution

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3 years ago

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Red and white paint are mixed to make pink paint. If the amount of red paint needed is half the amount of white paint, how many

Lady_Fox [76]

Answer:

We will need about 3.3 gallons of red paint.

Step-by-step explanation:

Let

r = amount of red paint

w = amount of white paint

The amount of red paint is half the amount of white paint.

r = 1/2 w

w = 2r [1]

We need to make a total of 10 gallons. Then,

r + w = 10 [2]

Replacing [1] in [2]

r + (2r) = 10

3r = 10

r = 3.3

We will need about 3.3 gallons of red paint.

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3 years ago

you deposited $1275.00 in your savings account . your simple interest rate is 3.75% annually. How much will your total account b

Lera25 [3.4K]

Answer:

$1,322.81

Step-by-step explanation:

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2 years ago

If a= 2,b= -1,c= -3 and d = -2 evaluate the following Q1. ab-3b+4d , Q2. 5abd+3bc-2ax and Q3. 2(ab)^2+bc^2

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Answer:

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3 years ago

If P is the orthocenter of △ABC, AB = 13, BF = 9,and FC = 5.6, find each measure & the perimeter of triangle ABC.

harina [27]

Answer:

$Perimeter = 38.6$

Step-by-step explanation:

Given

$A\ B = 13$

$B\ F = 9$

$F\ C = 5.6$

Required

Calculate the perimeter of A B C

To calculate the perimeter of A B C, we sum up the sides of the triangle

i.e.

$Perimeter = A B + B\ C + A\ C$

AB is given in the question already.

So, we need to calculate B F and F C

To solve for BF, we consider triangle B F C

Using Pythagoras Theorem, we have:

$B\ C^2 = B\ F^2 + F\ C^2$

Substitute values for BF and FC;

$B\ C^2 = 9^2 + 5.6^2$

$B\ C^2 = 81 + 31.36$

$B\ C^2 = 112.36$

$B\ C^2= \sqrt{112.36$

$B\ C = 10.6$

Next, we calculate A C.

To calculate A C, we need to calculate A F, considering triangle B F A

Using Pythagoras Theorem, we have:

$A\ B^2 = B\ F^2 + A\ F^2$

Substitute values for B F and A B;

$13^2 = 9^2 + A\ F^2$

$169= 81 + A\ F^2$

$A\ F^2 = 169 - 81$

$A\ F^2 = 88$

$A\ F = \sqrt{88$

$A\ F = 9.4$

Since F lies on line A C:

$A\ C = A\ F + F\ C$

$A\ C = 9.4 + 5.6$

$A\ C = 15.0$

Recall that:

$Perimeter = A\ B + B\ C + A\ C$

$Perimeter = 13 + 10.6 + 15.0$

$Perimeter = 38.6$

<em>Hence, the perimeter is 38.6</em>

3 0

3 years ago