We will define the following variables to solve the problem:
s: normal speed
t: normal time
We write the following system of equations:
6 = s * t
6 = (s + 3) * (t-7)
Rewriting the equation two we have:
6 = s * t -7s + 3t -21
Substituting:
s = 6 / t
6 = (6 / t) * t -7 (6 / t) + 3t -21
Multiplying both sides by t:
6t = 6t - 42 + 3t ^ 2 - 21t
Rewriting:
3t ^ 2 - 21t - 42 = 0
We take the positive root:
t = 7/2 + root (105) / 2
t = 8.62 h
We look for the value of the speed:
s = 6 / t
s = 6 / 8.62
s = 0.696 km / h
Answer:
she did travel 0.696 kilometers per hour
Yes it can be simplified, and the answer would be 4/5 (you would divide each by 3)
Answer:
B) 30
Step-by-step explanation:
The interquartile range in 100 to 130.
130-100=30
Answer:
<h2>50h miles</h2>
Step-by-step explanation:
For us to write a math expression for the problem, we will use the formula for calculating speed.
Speed is the change of distance of a body with respect to time.
Mathematically, Speed = Distance/Time
Distance = Speed * Time
If Lumpy drove for h hours at 50 mph, then Lumpy speed = 50mph and time = h hours.
Substituting the given parameters into the formula to get the distance;
Distance = 50mph * h hours
Distance = 50h miles
<em>Hence the math expression that modeled how far Lumpy drive is 50h miles</em>
Y = -x/3 + b1 = -3/3 + b
substitute values of point1 = -1 + b
then reduce2 = b
add one to both sides y = -x/3 + 2
